[英]Python - how to get all the values of nested dictionaries as a single List[dict]?
[英]Get all values from nested dictionaries in python
我有一些字典的字典,像这样:
a['b']['c']['d']['answer'] = answer1
a['b']['c']['e']['answer'] = answer2
a['b']['c']['f']['answer'] = answer3
....
a['b']['c']['d']['conf'] = conf1
a['b']['c']['e']['conf'] = conf2
a['b']['c']['f']['conf'] = conf3
有没有一种快速的方法来获取第三级(d,e,f)所有元素的所有答案的值列表?
具体来说,我想知道是否有任何实现通配符的机制(例如, a['b']['c']['*']['answer'].values()
更新到目前为止我发现的最快方法是:
[x['answer'] for x in a['b']['c'].values()]
在Python3中,我们可以为此构建一个简单的生成器:
def NestedDictValues(d):
for v in d.values():
if isinstance(v, dict):
yield from NestedDictValues(v)
else:
yield v
a={4:1,6:2,7:{8:3,9:4,5:{10:5},2:6,6:{2:7,1:8}}}
list(NestedDictValues(a))
输出是:
[1, 2, 3, 4, 6, 5, 8, 7]
这是所有的价值观。
您可以使用简单的列表理解:
[a['b']['c'][key]['answer'] for key in a['b']['c'].keys()]
Out[11]: ['answer1', 'answer2', 'answer3']
如果你想得到所有的答案和conf等你可以这样做:
[[a['b']['c'][key][type] for key in a['b']['c'].keys()] for type in a['b']['c']['d'].keys()]
Out[15]: [['conf1', 'conf2', 'conf3'], ['answer1', 'answer2', 'answer3']]
我会使用递归生成器函数来做到这一点:
def d_values(d, depth):
if depth == 1:
for i in d.values():
yield i
else:
for v in d.values():
if isinstance(v, dict):
for i in d_values(v, depth-1):
yield i
例:
>>> list(d_values({1: {2: 3, 4: 5}}, 2))
[3, 5]
在你的情况下,这将为每个项目提供一个字典,如{'answer': answer1, 'conf': conf1}
,因此您可以使用:
list(d['answer'] for d in d_values(a, 3))
只是为了回答这个主题,从我的问题的“更新状态”中复制我的解决方案:
[x['answer'] for x in a['b']['c'].values()]
希望这可以提供帮助。
list(map(lambda key: a['b']['c'][key], a['b']['c'].keys()))
您可以使用NestedDict
。 首先,让我重新创建你的字典
>>> from ndicts.ndicts import NestedDict
>>> nd = NestedDict.from_product("b", "c", "def", ["answer", "conf"])
NestedDict({
'b': {
'c': {
'd': {'answer': None, 'conf': None},
'e': {'answer': None, 'conf': None},
'f': {'answer': None, 'conf': None}
}
}
})
然后使用空字符串作为通配符
>>> nd_extract = nd.extract["b", "c", "", "answer"]
>>> nd_extract
NestedDict({
'b': {
'c': {
'd': {'answer': None},
'e': {'answer': None},
'f': {'answer': None}
}
}
})
最终得到值
>>> list(nd_extract.values())
[None, None, None]
安装ndicts
pip install ndicts
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.