[英]How to assign values from one array to another for n times
我正在尝试创建谁在哪一天使用特定物品的时间表。
我有2个数组。 一个带有日期 , 另一个带有名称,以及他们可以使用多少天。
我设法使用此创建日期数组。
function dateArray($from, $to, $value = NULL) {
$begin = new DateTime($from);
$end = new DateTime($to);
$interval = DateInterval::createFromDateString('1 day');
$days = new DatePeriod($begin, $interval, $end);
$baseArray = array();
foreach ($days as $day) {
$dateKey = $day->format("d-m-Y");
$baseArray[$dateKey] = $value;
}
return $baseArray;
}
$dates_array = dateArray('01-01-2014', '30-09-2014',true);
print_r($dates_array );
这给我日期
Array
(
[01-01-2014] => 1
[02-01-2014] => 1
[03-01-2014] => 1
[04-01-2014] => 1
[05-01-2014] => 1
[06-01-2014] => 1
[07-01-2014] => 1
[08-01-2014] => 1
[09-01-2014] => 1
and so on.
)
我还有另一个名称数组,名称作为键 , 天作为值 ,他们可以使用这样的项目。
$names_array = array("name1" => "4", "name2" => "3", "name3" => "1");
现在,我想根据该人可以使用多少天为该日期指定名称。 像这样。 我需要我的最终输出数组是这样的
Array
(
[01-01-2014] => name1
[02-01-2014] => name1
[03-01-2014] => name1
[04-01-2014] => name1
[05-01-2014] => name2
[06-01-2014] => name2
[07-01-2014] => name2
[08-01-2014] => name3
[09-01-2014] => name1
and so on. notice name1 comes again
)
所以我试图获得如上所述的输出,但是我在foreach中的while循环中失败了。 到目前为止,我已经尝试过了。
function dateArray($from, $to, $value = NULL) {
$begin = new DateTime($from);
$end = new DateTime($to);
$interval = DateInterval::createFromDateString('1 day');
$days = new DatePeriod($begin, $interval, $end);
$baseArray = array();
foreach ($days as $day) {
$dateKey = $day->format("d-m-Y");
$baseArray[$dateKey] = $value;
}
return $baseArray;
}
$dates_array = dateArray('01-01-2014', '30-09-2014',true);
$names_array = array("name1" => "4", "name2" => "3", "name3" => "1");
print_r($dates_array );
$new_dates = array();
foreach($dates_array as $dates => $key){
//echo $dates;
foreach ($names_array as $name => $days){
while($days <= 1){
$new_dates[$dates] = $name ;
$days = $days - 1;
}
}
}
print_r($new_dates);
但是我的最终数组为空。
那么我该如何解决呢?
您可以使用MultipleIterator
,从而在需要时第二个数组(名称)循环:
$names_array = array();
// unwind the array values
foreach (array("name1" => "4", "name2" => "3", "name3" => "1") as $value => $freq) {
for ($i = 0; $i < $freq; ++$i) {
$names_array[] = $value;
}
}
// attach both arrays
$m = new MultipleIterator;
$m->attachIterator(new ArrayIterator(array_keys($dates_array)));
$m->attachIterator(new InfiniteIterator(new ArrayIterator($names_array)));
// build final array
$result = array();
foreach ($m as $value) {
$result[$value[0]] = $value[1];
}
它可能应该像这样...
while($days <= 1){
$new_dates[$dates] = $name ;
$names_array[$name] = $days - 1;
}
嗨,你可以试试这个
$dates_array = array_keys(dateArray('01-01-2014', '30-09-2014',true));
$names_array = array("name1" => "4", "name2" => "3", "name3" => "1");
$new_dates = array();
$daysindex = 0;
while($daysindex < count($dates_array)){
foreach ($names_array as $name => $day){
for($x = 0; $x<$day; $x++){
if(isset($dates_array[$daysindex])){
$new_dates[$dates_array[$daysindex]] = $name ;
$daysindex++;
}
}
}
}
print_r($new_dates);
$dates = dateArray('01-01-2014', '30-09-2014',true);
$names = array('name1' => 4,'name2' => 3,'name3' => 1);
$count = current($names);
$name = key($names);
foreach($dates as &$value) {
$value = $name;
//if we've displayed a name $count times, move to the next name
if(--$count == 0) {
//if we're at the end of $names, wrap around
if(false === next($names)) {
reset($names);
}
$count = current($names);
$name = key($names);
}
}
print_r($dates);
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