在 Javascript 中获取周一开始和周日结束的一周开始和结束

Question

    function getStartAndEndOfWeek(date) {

        var curr = date ? new Date(date) : new Date();
        var first = curr.getDate() - curr.getDay(); 

        var firstday = new Date(curr.setDate(first));
        var lastday = new Date(curr.setDate(firstday.getDate() + 6));

        return [firstday, lastday];

    }

我无法将一周的开始设置为星期一。 上面的代码将第一天作为星期日。 此外，如果我们添加 first plus one，它将以星期一为开始，但问题在于让我们说（06/29/2014，星期日）是输入，它应该返回（06/23/2014 作为开始和 06 /29/2014) 作为结尾。 我们怎样才能做到这一点？ 如果我添加“first + 1”，它将返回 06/30/2014 作为开始日期和 07/06/2014 作为结束日期。 有什么帮助吗？ 谢谢。

回答：

    function getStartAndEndOfWeek(date) {

        //Calculating the starting point

        var curr = date ? new Date(date) : new Date();
        var first = curr.getDate() - dayOfWeek(curr);

        var firstday, lastday;

        if (first < 1) {
            //Get prev month and year
            var k = new Date(curr.valueOf());
            k.setDate(1);
            k.setMonth(k.getMonth() - 1);
            var prevMonthDays = new Date(k.getFullYear(), (k.getMonth() + 1), 0).getDate();

            first = prevMonthDays - (dayOfWeek(curr) - curr.getDate());
            firstday = new Date(k.setDate(first));
            lastday = new Date(k.setDate(first + 6));
        } else {
            // First day is the day of the month - the day of the week
            firstday = new Date(curr.setDate(first));
            lastday = new Date(curr.setDate(first + 6));
        }

        return [firstday, lastday];            
    }

    function dayOfWeek(date, firstDay) {
        var daysOfWeek = {
            sunday: 0,
            monday: 1,
            tuesday: 2,
            wednesday: 3,
            thursday: 4,
            friday: 5,
            saturday: 6,
        };
        firstDay = firstDay || "monday";
        var day = date.getDay() - daysOfWeek[firstDay];
        return (day < 0 ? day + 7 : day);
    }

Answer 1

如何制作一种简单的方法来让您轻松地控制一周的第一天：

(function() {
  var original = Date.prototype.getDay;
  var daysOfWeek = {
    sunday: 0,
    monday: 1,
    tuesday: 2,
    wednesday: 3,
    thursday: 4,
    friday: 5,
    saturday: 6,
  };

  Date.prototype.getDay = function(weekBegins) {
    weekBegins = (weekBegins || "sunday").toLowerCase();
    return (original.apply(this) + 7 - daysOfWeek[weekBegins]) % 7;
  };
})();

然后，您可以简单地使用：

var first = curr.getDate() - curr.getDay("monday"),
    last  = first + 6;

Answer 2

您可以通过移动getDay（）的结果，然后将结果取模，首先将其设置为星期一。

var first = curr.getDate() - ((curr.getDay() + 6) % 7); 

Answer 3

简单多了

 var numberdayweek = [6,0,1,2,3,4,5]; fecha = new Date(); console.log(numberdayweek[fecha.getDay()]);

Answer 4

找到其他解决方案：

 const getDayIndexMondaySunday = (date) =>date.getDay() === 0 ? 6 : date.getDay() - 1 // Result on Today console.log(getDayIndexMondaySunday(new Date()));