sql插入查询

Question

请帮忙！

此INSERT INTO查询有什么问题？

这是在newUser.php页面上进行查询之前

$result2=mysqli_query($con,"SELECT count(*) AS count FROM boards");
while($row2 = mysqli_fetch_array($result2)){
    $postNumber=$row2["count"];
}
echo $postNumber;
echo $_POST['bday'];

这是查询

mysqli_query($con,"INSERT INTO users (userID, profPicLoc, age, username, realName, birthday, password, meBoardID, email) VALUES (0, 'aa', 17, '" . $_POST['username2'] . "', '" . $_POST['name'] . "', '" . $_POST['bday'] . "', '" . $_POST['password2'] . "', " . $postNumber+2 . ", '" . $_POST['email'] . "')";

正确建立了到数据库的连接，用户标识为自动递增，数据库中的生日字段为DATE类型

它从另一页上的此表单中接收信息。

<form action="newUser.php" method="post">
</br>Name: <input type="text" name="name"></input></br>
Username: @<input type="text" name="username2"></input></br>
Password: <input type="password" name="password2"></input></br>
Email: <input type="text" name="email"></input></br>
Birthday: <input type="date" name="bday"></br>
<input type="submit"></input>
</form>

Answer 1

mysqli_query()括号关闭是错误的。 最后需要再加上一个右括号。 如果是AI，则从插入中删除user_id

mysqli_query($con,"INSERT INTO users (profPicLoc, age, username, realName, birthday, password, meBoardID, email) 
VALUES ('aa', 17, '" . $_POST['username2'] . "', '" . $_POST['name'] . "', '" . $_POST['bday'] . "', '" . $_POST['password2'] . "', " . $postNumber+2 . ", '" . $_POST['email'] . "')");

Answer 2

用它：

mysqli_query($con,"INSERT INTO users (profPicLoc, age, username, realName, birthday, password, meBoardID, email) VALUES ('aa', 17, '" . $_POST['username2'] . "', '" . $_POST['name'] . "', '" . $_POST['bday'] . "', '" . $_POST['password2'] . "', " . $postNumber+2 . ", '" . $_POST['email'] . "')";

插入时，切勿在主键包含自动递增的列。