sql插入查詢

Question

請幫忙！

此INSERT INTO查詢有什么問題？

這是在newUser.php頁面上進行查詢之前

$result2=mysqli_query($con,"SELECT count(*) AS count FROM boards");
while($row2 = mysqli_fetch_array($result2)){
    $postNumber=$row2["count"];
}
echo $postNumber;
echo $_POST['bday'];

這是查詢

mysqli_query($con,"INSERT INTO users (userID, profPicLoc, age, username, realName, birthday, password, meBoardID, email) VALUES (0, 'aa', 17, '" . $_POST['username2'] . "', '" . $_POST['name'] . "', '" . $_POST['bday'] . "', '" . $_POST['password2'] . "', " . $postNumber+2 . ", '" . $_POST['email'] . "')";

正確建立了到數據庫的連接，用戶標識為自動遞增，數據庫中的生日字段為DATE類型

它從另一頁上的此表單中接收信息。

<form action="newUser.php" method="post">
</br>Name: <input type="text" name="name"></input></br>
Username: @<input type="text" name="username2"></input></br>
Password: <input type="password" name="password2"></input></br>
Email: <input type="text" name="email"></input></br>
Birthday: <input type="date" name="bday"></br>
<input type="submit"></input>
</form>

Answer 1

mysqli_query()括號關閉是錯誤的。 最后需要再加上一個右括號。 如果是AI，則從插入中刪除user_id

mysqli_query($con,"INSERT INTO users (profPicLoc, age, username, realName, birthday, password, meBoardID, email) 
VALUES ('aa', 17, '" . $_POST['username2'] . "', '" . $_POST['name'] . "', '" . $_POST['bday'] . "', '" . $_POST['password2'] . "', " . $postNumber+2 . ", '" . $_POST['email'] . "')");

Answer 2

用它：

mysqli_query($con,"INSERT INTO users (profPicLoc, age, username, realName, birthday, password, meBoardID, email) VALUES ('aa', 17, '" . $_POST['username2'] . "', '" . $_POST['name'] . "', '" . $_POST['bday'] . "', '" . $_POST['password2'] . "', " . $postNumber+2 . ", '" . $_POST['email'] . "')";

插入時，切勿在主鍵包含自動遞增的列。