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[英]How to export data from more than one tables in one csv file without joins in php
[英]How to Export data from 3 tables in one .csv file php
我想从3个表中导出数据而无需在一个.csv文件中进行联接。 我正在尝试加入,但没有得到想要的结果。
下面是我的表结构
$mysql_host = DB_HOST;
$mysql_user = DB_USER;
$mysql_pass = DB_PASSWORD;
$mysql_db = DB_NAME;
$pre = $wpdb->prefix;
$link = mysql_connect($mysql_host, $mysql_user, $mysql_pass) or die('Could not connect: ' . mysql_error());
mysql_select_db($mysql_db, $link) or die('Could not select database: ' . $mysql_db);
$query = "SELECT plist.*, psong.*, prate.*
FROM " . $pre . "foo_playlists As plist
LEFT JOIN " . $pre . "foo_songs As psong
On plist.playlist_name = psong.splaylist_name
LEFT JOIN " . $pre . "foo_rating As prate
On psong.song_id = prate.rsong_id";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
$line = "";
$comma = "";
foreach ($row as $name => $value) {
$line .= $comma . '"' . str_replace('"', '""', $name) . '"';
$comma = ",";
}
$line .= "\n";
$out = $line;
mysql_data_seek($result, 0);
while ($row = mysql_fetch_assoc($result)) {
$line = "";
$comma = "";
foreach ($row as $value) {
$line .= $comma . '"' . str_replace('"', '""', $value) . '"';
$comma = ",";
}
$line .= "\n";
$out.=$line;
}
$csv_file_name = 'songs_' . date('Ymd_His') . '.csv'; # CSV FILE NAME WILL BE table_name_yyyymmdd_hhmmss.csv
header("Content-type: text/csv");
header("Content-Disposition: attachment; filename=" . $csv_file_name);
header("Content-Description:File Transfer");
header('Content-Transfer-Encoding: binary');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Type: application/octet-stream');
echo __($out, "foo");
exit;
我得到了this result
,我想要这个desired result
我怎样才能做到这一点?
好吧,您的问题是您无法在一个唯一的MySQL查询中同时检索所有数据,因为它们不是相关数据。 您的问题只是输出,因此,您只需要将3组结果关联到一个数组中。 要做到这一点:
执行这三个查询,并将它们保存在三个不相关的数组中。
与您将与所有人共享的密钥相关联。
循环所有将值分配给主“输出”数组的数组。
这样,您将拥有可以输出以获得所需CSV的数组。 出于示例的原因,由于无法使用您的var和查询编写有效的代码,因此编写了以下示例。 它具有3个不同的数组,您必须从数据库中获取模拟数据,但是您可以理解这个想法。 只需复制并粘贴,您将获得实时示例:
<?php
$playlists = array(
array(
'id' => 1
, 'data' => 'playlist1'
)
, array(
'id' => 2
, 'data' => 'playlist2'
)
, array(
'id' => 3
, 'data' => 'playlist3'
)
);
$songs = array(
array(
'id' => 1
, 'data' => 'song1'
)
, array(
'id' => 2
, 'data' => 'song2'
)
, array(
'id' => 3
, 'data' => 'song3'
)
, array(
'id' => 4
, 'data' => 'song4'
)
, array(
'id' => 5
, 'data' => 'song5'
)
);
$rates = array(
array(
'id' => 1
, 'data' => 'rating1'
)
, array(
'id' => 2
, 'data' => 'rating2'
)
, array(
'id' => 3
, 'data' => 'rating3'
)
, array(
'id' => 4
, 'data' => 'rating4'
)
, array(
'id' => 5
, 'data' => 'rating5'
)
, array(
'id' => 6
, 'data' => 'rating6'
)
);
// Count all the arrays and get the bigger:
$num = 0;
$play_num = count( $playlists );
$num = ($play_num > $num) ? $play_num : $num;
$song_num = count( $songs );
$num = ($song_num > $num) ? $song_num : $num;
$rate_num = count( $rates );
$num = ($rate_num > $num) ? $rate_num : $num;
$output = array();
for ( $i = 0; $i<=$num; $i++ ) {
$output[] = array(
'id_playlist' => !empty( $playlists[$i]['id'] ) ? $playlists[$i]['id'] : ''
, 'data_playlist' => !empty( $playlists[$i]['data'] ) ? $playlists[$i]['data'] : ''
, 'id_song' => !empty( $songs[$i]['id'] ) ? $songs[$i]['id'] : ''
, 'data_song' => !empty( $songs[$i]['data'] ) ? $songs[$i]['data'] : ''
, 'id_rate' => !empty( $rates[$i]['id'] ) ? $rates[$i]['id'] : ''
, 'data_rate' => !empty( $rates[$i]['data'] ) ? $rates[$i]['data'] : ''
);
}
foreach ( $output as $out ) {
echo implode( ' - ', $out);
echo '<br>';
}
1 - playlist1 - 1 - song1 - 1 - rating1
2 - playlist2 - 2 - song2 - 2 - rating2
3 - playlist3 - 3 - song3 - 3 - rating3
- - 4 - song4 - 4 - rating4
- - 5 - song5 - 5 - rating5
- - - - 6 - rating6
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