如何從一個.csv文件php中的3個表中導出數據

Question

我想從3個表中導出數據而無需在一個.csv文件中進行聯接。 我正在嘗試加入，但沒有得到想要的結果。

下面是我的表結構

Playlist Songs Rating

碼

$mysql_host = DB_HOST;
$mysql_user = DB_USER;
$mysql_pass = DB_PASSWORD;
$mysql_db = DB_NAME;

$pre = $wpdb->prefix;

$link = mysql_connect($mysql_host, $mysql_user, $mysql_pass) or die('Could not connect: ' . mysql_error());

mysql_select_db($mysql_db, $link) or die('Could not select database: ' . $mysql_db);

$query = "SELECT plist.*, psong.*, prate.* 
          FROM " . $pre . "foo_playlists As plist 
          LEFT JOIN " . $pre . "foo_songs As psong
          On plist.playlist_name = psong.splaylist_name 
          LEFT JOIN " . $pre . "foo_rating As prate
          On psong.song_id = prate.rsong_id";

$result = mysql_query($query);
$row = mysql_fetch_assoc($result);

$line = "";
$comma = "";

foreach ($row as $name => $value) {
   $line .= $comma . '"' . str_replace('"', '""', $name) . '"';
   $comma = ",";
}
    $line .= "\n";
    $out = $line;
    mysql_data_seek($result, 0);
    while ($row = mysql_fetch_assoc($result)) {
        $line = "";
        $comma = "";
        foreach ($row as $value) {
            $line .= $comma . '"' . str_replace('"', '""', $value) . '"';
            $comma = ",";
        }
        $line .= "\n";
        $out.=$line;
    }
    $csv_file_name = 'songs_' . date('Ymd_His') . '.csv'; # CSV FILE NAME WILL BE table_name_yyyymmdd_hhmmss.csv
    header("Content-type: text/csv");
    header("Content-Disposition: attachment; filename=" . $csv_file_name);
    header("Content-Description:File Transfer");
    header('Content-Transfer-Encoding: binary');
    header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
    header('Pragma: public');
    header('Content-Type: application/octet-stream');
    echo __($out, "foo");

    exit;

我得到了this result ，我想要這個desired result

我怎樣才能做到這一點？

Answer 1

好吧，您的問題是您無法在一個唯一的MySQL查詢中同時檢索所有數據，因為它們不是相關數據。 您的問題只是輸出，因此，您只需要將3組結果關聯到一個數組中。 要做到這一點：

• 執行這三個查詢，並將它們保存在三個不相關的數組中。

• 與您將與所有人共享的密鑰相關聯。

• 循環所有將值分配給主“輸出”數組的數組。

這樣，您將擁有可以輸出以獲得所需CSV的數組。 出於示例的原因，由於無法使用您的var和查詢編寫有效的代碼，因此編寫了以下示例。 它具有3個不同的數組，您必須從數據庫中獲取模擬數據，但是您可以理解這個想法。 只需復制並粘貼，您將獲得實時示例：

<?php

$playlists  = array(
    array(
        'id'    => 1
    ,   'data'  => 'playlist1'
    )
,   array(
        'id'    => 2
    ,   'data'  => 'playlist2'
    )
,   array(
        'id'    => 3
    ,   'data'  => 'playlist3'
    )
);

$songs  = array(
    array(
        'id'    => 1
    ,   'data'  => 'song1'
    )
,   array(
        'id'    => 2
    ,   'data'  => 'song2'
    )
,   array(
        'id'    => 3
    ,   'data'  => 'song3'
    )
,   array(
        'id'    => 4
    ,   'data'  => 'song4'
    )
,   array(
        'id'    => 5
    ,   'data'  => 'song5'
    )
);
$rates  = array(
    array(
        'id'    => 1
    ,   'data'  => 'rating1'
    )
,   array(
        'id'    => 2
    ,   'data'  => 'rating2'
    )
,   array(
        'id'    => 3
    ,   'data'  => 'rating3'
    )
,   array(
        'id'    => 4
    ,   'data'  => 'rating4'
    )
,   array(
        'id'    => 5
    ,   'data'  => 'rating5'
    )
,   array(
        'id'    => 6
    ,   'data'  => 'rating6'
    )
);

// Count all the arrays and get the bigger:
$num        = 0;
$play_num   = count( $playlists );
$num        = ($play_num > $num) ? $play_num : $num;

$song_num   = count( $songs );
$num        = ($song_num > $num) ? $song_num : $num;

$rate_num   = count( $rates );
$num        = ($rate_num > $num) ? $rate_num : $num;


$output = array();
for ( $i = 0; $i<=$num; $i++ ) {
    $output[]   = array(
        'id_playlist'   => !empty( $playlists[$i]['id'] )   ? $playlists[$i]['id']   : ''
    ,   'data_playlist' => !empty( $playlists[$i]['data'] ) ? $playlists[$i]['data'] : ''
    ,   'id_song'       => !empty( $songs[$i]['id'] )       ? $songs[$i]['id']       : ''
    ,   'data_song'     => !empty( $songs[$i]['data'] )     ? $songs[$i]['data']     : ''
    ,   'id_rate'       => !empty( $rates[$i]['id'] )       ? $rates[$i]['id']       : ''
    ,   'data_rate'     => !empty( $rates[$i]['data'] )     ? $rates[$i]['data']     : ''
    );
}

foreach ( $output as $out ) {
    echo implode( ' - ', $out);
    echo '<br>';
}

輸出：

1 - playlist1 - 1 - song1 - 1 - rating1
2 - playlist2 - 2 - song2 - 2 - rating2
3 - playlist3 - 3 - song3 - 3 - rating3
  -           - 4 - song4 - 4 - rating4
  -           - 5 - song5 - 5 - rating5
  -           -   -       - 6 - rating6