Celery：将每个任务运行记录到自己的文件中？

Question

我希望运行的每个作业都记录到文件名是 taskid 的 logs/ 目录中它自己的文件。

logger = get_task_logger(__name__)

@app.task(base=CallbackTask)
def calc(syntax):
    some_func()
    logger.info('started')

在我的工作人员中，我使用-f参数将日志文件设置为 output 。 我想确保它将每个任务输出到它自己的日志文件中。

Answer 1

好像我晚了3年。 不过，这是我的解决方案，灵感来自@Mikko Ohtamaa 的想法。 我只是通过使用 Celery 信号和 python 的内置日志框架来准备和清理日志句柄，使它有点不同。

from celery.signals import task_prerun, task_postrun
import logging

# to control the tasks that required logging mechanism
TASK_WITH_LOGGING = ['Proj.tasks.calc']
@task_prerun.connect(sender=TASK_WITH_LOGGING)
def prepare_logging(signal=None, sender=None, task_id=None, task=None, args=None, kwargs=None)
    logger = logging.getLogger(task_id)
    formatter = logging.Formatter('[%(asctime)s][%(levelname)s] %(message)s')
    # optionally logging on the Console as well as file
    stream_handler = logging.StreamHandler()
    stream_handler.setFormatter(formatter)
    stream_handler.setLevel(logging.INFO)
    # Adding File Handle with file path. Filename is task_id
    task_handler = logging.FileHandler(os.path.join('/tmp/', task_id+'.log'))
    task_handler.setFormatter(formatter)
    task_handler.setLevel(logging.INFO)
    logger.addHandler(stream_handler)
    logger.addHandler(task_handler)

@task_postrun.connect(sender=TASK_WITH_LOGGING)
def close_logging(signal=None, sender=None, task_id=None, task=None, args=None, kwargs=None, retval=None, state=None):
    # getting the same logger and closing all handles associated with it
    logger = logging.getLogger(task_id)
    for handler in logger.handlers:
        handler.flush()
        handler.close()
    logger.handlers = []

@app.task(base=CallbackTask, bind=True)
def calc(self, syntax):
    # getting logger with name Task ID. This is already
    # created and setup in prepare_logging
    logger = logging.getLogger(self.request.id)
    some_func()
    logger.info('started')

bind=True在这里是必要的，以便在任务中使用 id。 这将在每次执行任务calc时使用<task_id>.log创建单独的日志文件。

Answer 2

下面是我粗鲁的，写出来的，未经测试的方法。 将其视为指导而不是生产级代码。

def get_or_create_task_logger(func):
    """ A helper function to create function specific logger lazily. """

    # https://docs.python.org/2/library/logging.html?highlight=logging#logging.getLogger
    # This will always result the same singleton logger
    # based on the task's function name (does not check cross-module name clash, 
    # for demo purposes only)
    logger = logging.getLogger(func.__name__)

    # Add our custom logging handler for this logger only
    # You could also peek into Celery task context variables here
    #  http://celery.readthedocs.org/en/latest/userguide/tasks.html#context
    if len(logger.handlers) == 0:
        # Log to output file based on the function name
        hdlr = logging.FileHandler('%s.log' % func.__name__)
        formatter = logging.Formatter('%(asctime)s %(levelname)s %(message)s')
        hdlr.setFormatter(formatter)
        logger.addHandler(hdlr) 
        logger.setLevel(logging.DEBUG)

    return logger

@app.task(base=CallbackTask)
def calc(syntax):
    logger = get_or_create_task_logger(calc)
    some_func()
    logger.info('started')

Answer 3

这是我的代码，

import logging

from celery.app.log import TaskFormatter
from celery.signals import task_prerun, task_postrun

@task_prerun.connect
def overload_task_logger(task_id, task, args, **kwargs):
    logger = logging.getLogger("celery.task")
    file_handler = logging.FileHandler(f'/tmp/{task_id}.log')
    file_handler.setLevel(logging.INFO)
    file_handler.setFormatter(
        TaskFormatter("[%(asctime)s: %(levelname)s/%(processName)s] %(task_name)s[%(task_id)s]: %(message)s")
    )
    logger.addHandler(file_handler)


@task_postrun.connect
def cleanup_logger(task_id, task, args, **kwargs):
    logger = logging.getLogger("celery.task")
    for handler in logger.handlers:
        if isinstance(handler, logging.FileHandler) and handler.baseFilename == f'/tmp/{task_id}.log':
            logger.removeHandler(handler)

在 celery 上测试：v5.2.7