Python列表理解失败，并出现语法错误

Question

我正在从http://cscircles.cemc.uwaterloo.ca/15b-python-pushups/中进行练习3，我使代码工作了，但是想知道是否可以用更少的行数来做？ 这是我的解决方案：

los = [] # short for list of strings
while True:
   s = input()
   if s == '###': break
   los += s.lower().split() # making a list of lower case words from the input     sentences
test = []
for x in los:
   test += str(los.count(x)) # made a new list of the frequency of each word
a = test.index(max(test)) # variable a provides the location of them most frequent word
print (los[a]) # we know the position of the most frequent string, so find it in los.
# a is not needed but it looks neater

因此，这部分尤其令我不满意：

    for x in los:
       test += str(los.count(x))

我想这样写：

test += str(list.count(x)) for x in los

但这告诉我语法无效。任何提示吗？

Answer 1

我认为您想要的语法是：

  # No need for test = []
  test = [str(list.count(x)) for x in los]