[英]typedef function pointer -> initialization from incompatible pointer type
我无法理解此警告的原因:
menu-file-select.c:41:29: warning: initialization from incompatible pointer type
令人反感的代码是:
typedef int (*FileSelectFilter)(const char*, struct dirent*);
typedef struct {
const char *dir; //the directory path to read
const char *out; //where to copy the selected path
int outLen; //length of out buffer
FileSelectFilter *filter; //optional filter function
} FileSelectParams;
void showFileSelectMenu(FileSelectParams *params) {
/* ... */
FileSelectFilter filter = params->filter; // <-- warning generated here.
if(filter && !filter(path, ent)) continue;
/* ... */
}
int main(int argc, char **argv) {
/* ... */
FileSelectParams fsel = {
.dir = setting.lastpath,
.out = RomPath,
.outLen = sizeof(RomPath) - 1,
.filter = FileSelectFilter_Roms,
};
showFileSelectMenu(&fsel);
/* ... */
}
int FileSelectFilter_Roms(const char *path, struct dirent *file) {
/* ... */
}
据我所知, FileSelectFilter_Roms
与FileSelectFilter
typedef相匹配,所以我不明白为什么我被告知类型不兼容。 该程序似乎仍然可以运行,但是在这里出现此警告使我感到困扰。
您已将FileSelectFilter
定义为指向typedef中的函数的指针:
typedef int (*FileSelectFilter)(const char*, struct dirent*);
在FileSelectPararms
,将filter
成员定义为:
FileSelectFilter *filter;
这意味着filter
实际上是指向函数的指针。 这就是为什么在分配FileSelectFilter filter = params->filter;
出错的原因FileSelectFilter filter = params->filter;
。
filter
成员应简单定义为:
FileSelectFilter filter;
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