如何在cout上使用isatty(),还是可以假设cout ==文件描述符1? [英]how to use isatty() on cout, or can I assume that cout == file descriptor 1?
如何在不使用插入排序更改原始向量的情况下对2d向量进行排序 [英]how can i sort a 2d vector without change the original vector with insertion sort
为什么我得到错误“'cout'在命名空间'std'中没有命名类型”当我使用“使用cout = std :: cout;”? [英]Why do I get error “'cout' in namespace 'std' does not name a type” when I use “using cout = std::cout;”?