![](/img/trans.png)
[英]Problems with JAXB, Marshal, - unable to marshal type “java.lang.String”
[英]Problems with JAXB, Marshal, - unable to marshal type “java.lang.String”
当我运行marshal操作时,我收到以下错误:
javax.xml.bind.MarshalException
- with linked exception:
[com.sun.istack.internal.SAXException2: unable to marshal type "java.lang.String" as an element because it is missing an @XmlRootElement annotation]
...
Caused by: com.sun.istack.internal.SAXException2: unable to marshal type "java.lang.String" as an element because it is missing an @XmlRootElement annotation
at com.sun.xml.internal.bind.v2.runtime.XMLSerializer.reportError(XMLSerializer.java:237)
at com.sun.xml.internal.bind.v2.runtime.LeafBeanInfoImpl.serializeRoot(LeafBeanInfoImpl.java:126)
at com.sun.xml.internal.bind.v2.runtime.XMLSerializer.childAsRoot(XMLSerializer.java:483)
at com.sun.xml.internal.bind.v2.runtime.MarshallerImpl.write(MarshallerImpl.java:308)
... 6 more
这是我编组的功能......
public StringBuffer Marshaller(Object marshall){ // make marshalling->Java to XML
StringWriter writer = new StringWriter();
try {
JAXBContext jaxbContext=JAXBContext.newInstance(marshall.getClass());
Marshaller jaxbMarshaller=jaxbContext.createMarshaller();
// çıktı
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(marshall, writer);
System.out.println(writer.getBuffer().toString());
} catch (PropertyException e) {
e.printStackTrace();
} catch (JAXBException e) {
e.printStackTrace();
}
return writer.getBuffer();
}
谢谢你的兴趣..
你不能只编组一个String
因为它没有任何根元素信息(因此有关缺少的@XmlRootElement
注释的例外),但你可以将它包装在JAXBElement
一个实例中,然后编组它。 JAXBElement
是向JAXB提供此根元素信息的另一种方法。
创建JAXBElement
示例
JAXBElement<String> jaxbElement =
new JAXBElement(new QName("root-element"),
String.class, string);
如果您从XML架构生成模型
如果您是从XML Schema创建了对象模型。 你有一个顶级的XML元素,它是一个像xs:string
这样的数据类型,然后在生成的ObjectFactory
类上会有一个方便的方法来帮助你创建JAXBElement
实例。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.