[英]Problems with JAXB, Marshal, - unable to marshal type “java.lang.String”
[英]Problems with JAXB, Marshal, - unable to marshal type “java.lang.String”
當我運行marshal操作時,我收到以下錯誤:
javax.xml.bind.MarshalException
- with linked exception:
[com.sun.istack.internal.SAXException2: unable to marshal type "java.lang.String" as an element because it is missing an @XmlRootElement annotation]
...
Caused by: com.sun.istack.internal.SAXException2: unable to marshal type "java.lang.String" as an element because it is missing an @XmlRootElement annotation
at com.sun.xml.internal.bind.v2.runtime.XMLSerializer.reportError(XMLSerializer.java:237)
at com.sun.xml.internal.bind.v2.runtime.LeafBeanInfoImpl.serializeRoot(LeafBeanInfoImpl.java:126)
at com.sun.xml.internal.bind.v2.runtime.XMLSerializer.childAsRoot(XMLSerializer.java:483)
at com.sun.xml.internal.bind.v2.runtime.MarshallerImpl.write(MarshallerImpl.java:308)
... 6 more
這是我編組的功能......
public StringBuffer Marshaller(Object marshall){ // make marshalling->Java to XML
StringWriter writer = new StringWriter();
try {
JAXBContext jaxbContext=JAXBContext.newInstance(marshall.getClass());
Marshaller jaxbMarshaller=jaxbContext.createMarshaller();
// çıktı
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(marshall, writer);
System.out.println(writer.getBuffer().toString());
} catch (PropertyException e) {
e.printStackTrace();
} catch (JAXBException e) {
e.printStackTrace();
}
return writer.getBuffer();
}
謝謝你的興趣..
你不能只編組一個String
因為它沒有任何根元素信息(因此有關缺少的@XmlRootElement
注釋的例外),但你可以將它包裝在JAXBElement
一個實例中,然后編組它。 JAXBElement
是向JAXB提供此根元素信息的另一種方法。
創建JAXBElement
示例
JAXBElement<String> jaxbElement =
new JAXBElement(new QName("root-element"),
String.class, string);
如果您從XML架構生成模型
如果您是從XML Schema創建了對象模型。 你有一個頂級的XML元素,它是一個像xs:string
這樣的數據類型,然后在生成的ObjectFactory
類上會有一個方便的方法來幫助你創建JAXBElement
實例。
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