RubyOnRails4呈现JSON时如何从has_many关系中排除属性

Question

有没有办法像我对@databases一样从：jobs中排除属性？ 我是红宝石和Rails的新手，所以我怀疑（希望：读到）我的语法错误，这很容易解决。

wants.json { render :json => @databases, :include => [:jobs], :except => [:id, :created_at, :updated_at] }

Answer 1

如果@databases对象的模型类具有has_many :jobs则可以执行以下操作：

render :json => @databases.to_json(:include => {:jobs => {:except => [:created_at, updated_at]}}, :except => [:id, :created_at, :updated_at])

Answer 2

解

已将=> { :except => [:id] }到:jobs

wants.json { render :json => @databases, :include => [:jobs => { :except => [:id] }, :except => [:id, :created_at, :updated_at] }