RubyOnRails4呈现JSON时如何从has_many关系中排除属性

Question

Is there a way to exclude properties from :jobs like I've done with @databases? I'm new to ruby and rails so I suspect (read: hope) that my syntax is wrong and this is an easy problem to fix.

wants.json { render :json => @databases, :include => [:jobs], :except => [:id, :created_at, :updated_at] }

Answer 1

如果@databases对象的模型类具有has_many :jobs则可以执行以下操作：

render :json => @databases.to_json(:include => {:jobs => {:except => [:created_at, updated_at]}}, :except => [:id, :created_at, :updated_at])

Answer 2

Solution

Added => { :except => [:id] } to :jobs

wants.json { render :json => @databases, :include => [:jobs => { :except => [:id] }, :except => [:id, :created_at, :updated_at] }