如何通过UnitySendMessage方法从Android Java项目中调用Unity C＃方法？

Question

我创建一个Unity项目，并将其添加到我的Android布局中。 一切都很好。 当我尝试使用UnityPlayer.UnitySendMessage（“ GameObject”，“ method”，“ message”）从我的Android项目中调用c＃方法时遇到问题。 我收到以下错误：找不到对象跳转！。 我读过很多类似的问题，但有人帮助我。

1. 在Unity中，我有一个gameobject调用Jump
2. C＃类的名称是Jump
3. 我构建一个android项目并在Eclipse中添加Staging Area文件夹（通过创建新的android项目）
4. 该项目被标记为图书馆
5. 我在我的图书馆添加classes.jar

我给你看我的android代码：

package com.example.footm;

import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

import android.app.Activity;
import android.os.Bundle;

import com.unity3d.player.UnityPlayer;
import com.unity3d.player.UnityPlayerActivity;
//Studio dei movimenti del soggetto

public class AvatarUnity extends UnityPlayerActivity {

    UnityPlayer mUnityPlayer;
    protected void onCreate(Bundle savedInstanceState){
        super.onCreate(savedInstanceState);
        MachineState.Avatar_Thread_isRunning = true;
        Thread AvatarThread = new Thread(new Runnable(){

            @Override
            public void run() {
                String start_string = "s";
                OutputStream os;
                byte[] byte_start = new byte[start_string.length()];
                byte_start=start_string.getBytes();
                try {

                     os = MachineState.socket.getOutputStream();
                     os.write(byte_start);
                     os.flush();
                } catch (IOException e1) {
                    // TODO Auto-generated catch block
                    MachineState.Avatar_Thread_isRunning=false;
                    e1.printStackTrace();
                }
                byte[] buffer_dati = new byte[1024];
                int count_bytes_read;
                int Pressure_back;
                int Pressure_front;
                //Valori baseline di pressione di un soggetto in piedi (punta e tacco della scarpa)
                int soglia_front = 120;
                int soglia_back = 120;

                InputStream is;
                try {
                    is = MachineState.socket.getInputStream();
                    while((count_bytes_read = is.read(buffer_dati))!=-1 && MachineState.Avatar_Thread_isRunning){
                        String data = new String(buffer_dati,0,count_bytes_read);
                        if(data.length()==19){
                            Pressure_back = Integer.parseInt(data.substring(10, 13), 16);
                            Pressure_front = Integer.parseInt(data.substring(13, 16), 16);
                            if(Pressure_back>soglia_back && Pressure_front>soglia_front){

                                doJump();


                            }

                        }
                    }
                } catch (IOException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }


            }

        });
        AvatarThread.start();


    }

    @Override
    public void onBackPressed(){
        Activity a = new Activity();
        a.onBackPressed();
    }

    public static void doJump(){
        com.unity3d.player.UnityPlayer.UnitySendMessage("Jump", "performJump", "doJump");
    }
}

这是我的Unity代码：

using UnityEngine;
using System.Collections;

public class Jump : MonoBehaviour {

    AndroidJavaClass androidClass;
    // Use this for initialization
    void Start () {
        AndroidJNIHelper.debug = true; 
        using (AndroidJavaClass jc = new AndroidJavaClass("com.unity3d.player.UnityPlayer")) { 
                jc.CallStatic ("UnitySendMessage", "Jump", "performJump", "doJump"); 
        }
//      AndroidJNI.AttachCurrentThread ();
//      androidClass = new AndroidJavaClass("com.example.footm.Avatar");

    }

    // Update is called once per frame
    void Update () {

    }

    public void performJump(string message){
        //Void esecuzione salto
        GameObject go2 = GameObject.Find ("myHumanoid");
        Animator anim = go2.GetComponent<Animator> ();
        anim.Play ("jump_1");
    }
}

Answer 1

您应该检查名称为“ Jump”的游戏对象是否在当前场景中退出。 自然地，

UnityPlayer. UnitySendMessage("Gameobject Name","Method","Message")

Answer 2

我认为您使用AndroidJavaClass的方式错误。

using (AndroidJavaClass jc = new
AndroidJavaClass("com.unity3d.player.UnityPlayer")) { 
//jc.CallStatic ("UnitySendMessage", "Jump", "performJump", "doJump"); 
jc.CallStatic("doJump");

您的android代码中没有称为“ UnitySendMessage”的方法