[英]how to transform following xml to another xml using xslt summary input xml element value should become the output xml tag with their values at runtime
如果input.xml具有键值对,则该文件可能是大文件,因此运行时输出应生成键成为输出标签名称,并且值将是使用xslt Input.xml的值。
<keyValueStr>
<key>memberId </key>
<value>12345</value>
</keyValueStr>
<keyValueStr>
<key>mbrAccountNumber</key>
<value>CO12345</value>
</keyValueStr>
<keyValueStr>
<key>grId</key>
<value>4568667</value>
</keyValueStr>
<keyValueStr>
<key>abc </key>
<value>111111</value>
</keyValueStr>
<keyValueStr>
<key>def</key>
<value>22222</value>
</keyValueStr>
<keyValueStr>
<key>ghi</key>
<value>33333</value>
</keyValueStr>
**output should like this:**
<memberMinimumInfoRequest>
<memberid>12345</memberId>
<mbrAccountNumber>CO12345</mbrAccountNumber>
<grId>4568667</grId>
<abc>111111</abc>
<def>22222</def>
<ghi>33333</ghi>
</memberMinimumInfoRequest>
如果每个成员的信息MemberId
键开头,则可以在包含元素的模板中使用xsl:for-each-group
( http://www.w3.org/TR/xslt20/#xsl-for-每个组 )以选择每个成员的信息并进行处理,例如:
<xsl:for-each-group select="keyValueStr"
group-starting-with="keyValueStr[. eq 'memberId ']">
<memberMinimumInfoRequest>
<xsl:apply-templates select="current-group()" />
</memberMinimumInfoRequest>
</xsl:for-each-group>
('memberId'中是否真的应该有空格?)
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