如何使用xslt摘要将以下xml转换为另一个xml摘要输入xml元素值应在运行时与其值一起成为输出xml标记

Question

if input.xml have key value pairs this may be large file so run time output should geneate key become the output tag name and value will be its value using xslt Input.xml

            <keyValueStr>
                <key>memberId </key>
                <value>12345</value>
            </keyValueStr>
            <keyValueStr>
                <key>mbrAccountNumber</key>
                <value>CO12345</value>
            </keyValueStr>
            <keyValueStr>
                <key>grId</key>
                <value>4568667</value>
            </keyValueStr>
            <keyValueStr>
                <key>abc </key>
                <value>111111</value>
            </keyValueStr>
            <keyValueStr>
                <key>def</key>
                <value>22222</value>
            </keyValueStr>
            <keyValueStr>
                <key>ghi</key>
                <value>33333</value>
            </keyValueStr>

**output should like this:**
<memberMinimumInfoRequest>
            <memberid>12345</memberId>
            <mbrAccountNumber>CO12345</mbrAccountNumber>
            <grId>4568667</grId>
            <abc>111111</abc>
            <def>22222</def>
            <ghi>33333</ghi>
</memberMinimumInfoRequest>

Answer 1

If the information for each member starts with a MemberId key, then in the template for the containing element you can use xsl:for-each-group ( http://www.w3.org/TR/xslt20/#xsl-for-each-group ) to select each member's information and process it, eg:

<xsl:for-each-group select="keyValueStr"
                    group-starting-with="keyValueStr[. eq 'memberId ']">
  <memberMinimumInfoRequest>
    <xsl:apply-templates select="current-group()" />
  </memberMinimumInfoRequest>
</xsl:for-each-group>

(Should there really be a space in 'memberId '?)