R：基于另一个data.frame独立于data.frame的行子集

Question

我有一个带有示例数据的input data.frame

input <- structure(list(NAME = structure(c(3L, 7L, 6L, 4L, 2L, 5L, 1L), .Label = c("Example2","Example7", "Test", "Test2", "Test3", "Test6", "Test77"), class = "factor"), REFERENCE = structure(c(2L, 3L, 1L, 1L, 4L, 2L, 1L), .Label = c("EXAMPLE5", "REGION1", "REGION2", "REGION77"), class = "factor"), VALUE = structure(c(1L,2L, 3L, 4L, 6L, 5L, 7L), .Label = c("120", "13", "14", "65", "89", "B", "C"), class = "factor")), .Names = c("NAME", "REFERENCE", "VALUE"), class = "data.frame", row.names = c(NA, -7L))
      NAME REFERENCE VALUE
1     Test   REGION1   120
2   Test77   REGION2    13
3    Test6  EXAMPLE5    14
4    Test2  EXAMPLE5    65
5 Example7  REGION77     B
6    Test3   REGION1    89
7 Example2  EXAMPLE5     C

我还有第二个data.frame filelist ，其中数据的排序如下。

filelist <- structure(list(NAME = structure(c(3L, 5L, 1L, 6L, 4L, 2L), .Label = c("","Example2", "Test", "Test2", "Test3", "Test6"), class = "factor"), REFERENCE = structure(c(3L, 3L, 1L, 2L, 2L, 2L), .Label = c("",  "EXAMPLE5", "REGION1"), class = "factor")), .Names = c("NAME","REFERENCE"), class = "data.frame", row.names = c(NA, -6L))
          NAME REFERENCE
    1     Test   REGION1
    2    Test3   REGION1
    3                   
    4    Test6  EXAMPLE5
    5    Test2  EXAMPLE5
    6 Example2  EXAMPLE5

filelist包含应写到单独的data.frames中的所有值，这些值由REFERENCE列分组（如下面的代码所示）。 到目前为止，我通过使用下面的代码并手动设置各列，然后将它们重新绑定在一起来做到这一点。 有没有一种方法可以独立完成？

# Manual selection REGION1
Test <- subset(input, NAME=="Test")
Test3 <- subset(input, NAME=="Test3")
# rbind them together
REGION1 <- rbind(Test, Test3)

# Manual selection EXAMPLE5
Test6 <- subset(input, NAME=="Test6")
Test2 <- subset(input, NAME=="Test2")
Example2 <- subset(input, NAME=="Example2")
# rbind them together
EXAMPLE5 <- rbind(Test6, Test2,Example2)

Answer 1

这可能会有所帮助，而且您需要做什么。 似乎您想合并输入和文件列表。 然后，您要为每个参考级别创建一个数据框。

library(dplyr)

ana <- filelist %>%
            left_join(., input)

split(ana, f = ana$REFERENCE )

#[[1]]
#  NAME REFERENCE VALUE
#3                 <NA>

#$EXAMPLE5
#      NAME REFERENCE VALUE
#4    Test6  EXAMPLE5    14
#5    Test2  EXAMPLE5    65
#6 Example2  EXAMPLE5     C

#$REGION1
#   NAME REFERENCE VALUE
#1  Test   REGION1   120
#2 Test3   REGION1    89

编辑

非常感谢@Richard Scriven。 这是OP想要的最后一步。

list2env(split(ana, f = ana$REFERENCE )[-1], .GlobalEnv)

#> EXAMPLE5
#      NAME REFERENCE VALUE
#4    Test6  EXAMPLE5    14
#5    Test2  EXAMPLE5    65
#6 Example2  EXAMPLE5     C