在 Swift 中将十六进制字符串转换为 NSData

Question

我在 Objective-C 中获得了将字符串转换为十六进制字符串的代码：

- (NSString *) CreateDataWithHexString:(NSString*)inputString {
    NSUInteger inLength = [inputString length];    
      
    unichar *inCharacters = alloca(sizeof(unichar) * inLength);
    [inputString getCharacters:inCharacters range:NSMakeRange(0, inLength)];
    
    UInt8 *outBytes = malloc(sizeof(UInt8) * ((inLength / 2) + 1));
    
    NSInteger i, o = 0;
    UInt8 outByte = 0;

    for (i = 0; i < inLength; i++) {
        UInt8 c = inCharacters[i];
        SInt8 value = -1;
        
        if      (c >= '0' && c <= '9') value =      (c - '0');
        else if (c >= 'A' && c <= 'F') value = 10 + (c - 'A');
        else if (c >= 'a' && c <= 'f') value = 10 + (c - 'a');
        
        if (value >= 0) {
            if (i % 2 == 1) {
                outBytes[o++] = (outByte << 4) | value;
                outByte = 0;
            } else {
                outByte = value;
            }
            
        } else {
            if (o != 0) break;
        }
    }
    
    NSData *a = [[NSData alloc] initWithBytesNoCopy:outBytes length:o freeWhenDone:YES];
    NSString* newStr = [NSString stringWithUTF8String:[a bytes]];
    return newStr;
}

我希望 Swift 也一样。 任何人都可以在 Swift 中翻译此代码，或者在 Swift 中是否有任何简单的方法可以做到这一点？

Answer 1

这是我的Data例程的十六进制字符串：

extension String {
    
    /// Create `Data` from hexadecimal string representation
    ///
    /// This creates a `Data` object from hex string. Note, if the string has any spaces or non-hex characters (e.g. starts with '<' and with a '>'), those are ignored and only hex characters are processed.
    ///
    /// - returns: Data represented by this hexadecimal string.
    
    var hexadecimal: Data? {
        var data = Data(capacity: count / 2)
        
        let regex = try! NSRegularExpression(pattern: "[0-9a-f]{1,2}", options: .caseInsensitive)
        regex.enumerateMatches(in: self, range: NSRange(startIndex..., in: self)) { match, _, _ in
            let byteString = (self as NSString).substring(with: match!.range)
            let num = UInt8(byteString, radix: 16)!
            data.append(num)
        }
        
        guard data.count > 0 else { return nil }
        
        return data
    }
    
}

为了完整起见，这是我的Data到十六进制字符串例程：

extension Data {
    
    /// Hexadecimal string representation of `Data` object.
    
    var hexadecimal: String {
        return map { String(format: "%02x", $0) }
            .joined()
    }
}

---

请注意，如上所示，我通常只在十六进制表示和NSData实例之间进行转换（因为如果信息可以表示为字符串，您可能一开始就不会创建十六进制表示）。 但是您最初的问题想要在十六进制表示和String对象之间进行转换，这可能看起来像这样：

extension String {
    
    /// Create `String` representation of `Data` created from hexadecimal string representation
    ///
    /// This takes a hexadecimal representation and creates a String object from that. Note, if the string has any spaces, those are removed. Also if the string started with a `<` or ended with a `>`, those are removed, too.
    ///
    /// For example,
    ///
    ///     String(hexadecimal: "<666f6f>")
    ///
    /// is
    ///
    ///     Optional("foo")
    ///
    /// - returns: `String` represented by this hexadecimal string.
    
    init?(hexadecimal string: String, encoding: String.Encoding = .utf8) {
        guard let data = string.hexadecimal() else {
            return nil
        }
        
        self.init(data: data, encoding: encoding)
    }
            
    /// Create hexadecimal string representation of `String` object.
    ///
    /// For example,
    ///
    ///     "foo".hexadecimalString()
    ///
    /// is
    ///
    ///     Optional("666f6f")
    ///
    /// - parameter encoding: The `String.Encoding` that indicates how the string should be converted to `Data` before performing the hexadecimal conversion.
    ///
    /// - returns: `String` representation of this String object.
    
    func hexadecimalString(encoding: String.Encoding = .utf8) -> String? {
        return data(using: encoding)?
            .hexadecimal
    }
    
}

然后你可以像这样使用上面的：

let hexString = "68656c6c 6f2c2077 6f726c64"
print(String(hexadecimal: hexString))

或者，

let originalString = "hello, world"
print(originalString.hexadecimalString())

有关早期 Swift 版本的上述排列，请参阅此问题的修订历史。

Answer 2

将十六进制字符串转换为数据和字符串：

斯威夫特1

func dataWithHexString(hex: String) -> NSData {
    var hex = hex
    let data = NSMutableData()
    while(countElements(hex) > 0) {
        var c: String = hex.substringToIndex(advance(hex.startIndex, 2))
        hex = hex.substringFromIndex(advance(hex.startIndex, 2))
        var ch: UInt32 = 0
        NSScanner(string: c).scanHexInt(&ch)
        data.appendBytes(&ch, length: 1)
    }
    return data
}

利用：

let data = dataWithHexString("68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
if let string = NSString(data: data, encoding: 1) {
    print(string) // hello, world
}

斯威夫特2

func dataWithHexString(hex: String) -> NSData {
    var hex = hex
    let data = NSMutableData()
    while(hex.characters.count > 0) {
        let c: String = hex.substringToIndex(hex.startIndex.advancedBy(2))
        hex = hex.substringFromIndex(hex.startIndex.advancedBy(2))
        var ch: UInt32 = 0
        NSScanner(string: c).scanHexInt(&ch)
        data.appendBytes(&ch, length: 1)
    }
    return data
}

利用：

let data = dataWithHexString("68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
if let string = String(data: data, encoding: NSUTF8StringEncoding) {
    print(string) //"hello, world"
}

斯威夫特3

func dataWithHexString(hex: String) -> Data {
    var hex = hex
    var data = Data()
    while(hex.characters.count > 0) {
        let c: String = hex.substring(to: hex.index(hex.startIndex, offsetBy: 2))
        hex = hex.substring(from: hex.index(hex.startIndex, offsetBy: 2))
        var ch: UInt32 = 0
        Scanner(string: c).scanHexInt32(&ch)
        var char = UInt8(ch)
        data.append(&char, count: 1)
    }
    return data
}

利用：

let data = dataWithHexString(hex: "68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
let string = String(data: data, encoding: .utf8) // "hello, world"

斯威夫特4

func dataWithHexString(hex: String) -> Data {
    var hex = hex
    var data = Data()
    while(hex.count > 0) {
        let subIndex = hex.index(hex.startIndex, offsetBy: 2)
        let c = String(hex[..<subIndex])
        hex = String(hex[subIndex...])
        var ch: UInt32 = 0
        Scanner(string: c).scanHexInt32(&ch)
        var char = UInt8(ch)
        data.append(&char, count: 1)
    }
    return data
}

利用：

let data = dataWithHexString(hex: "68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
let string = String(data: data, encoding: .utf8) // "hello, world"

Answer 3

斯威夫特 4 & 斯威夫特 5实施：

init?(hexString: String) {
  let len = hexString.count / 2
  var data = Data(capacity: len)
  var i = hexString.startIndex
  for _ in 0..<len {
    let j = hexString.index(i, offsetBy: 2)
    let bytes = hexString[i..<j]
    if var num = UInt8(bytes, radix: 16) {
      data.append(&num, count: 1)
    } else {
      return nil
    }
    i = j
  }
  self = data
}

用法：

let data = Data(hexString: "0a1b3c4d")

Answer 4

这是我的Swift 5方法：

• 确实处理“0x”前缀
• 使用下标而不是分配的 Array()，也没有 C 风格 [i+1]
• 将.hexadecimal添加到String.data(using encoding:) -> Data?

.

字符串扩展：

    extension String {
        enum ExtendedEncoding {
            case hexadecimal
        }

        func data(using encoding:ExtendedEncoding) -> Data? {
            let hexStr = self.dropFirst(self.hasPrefix("0x") ? 2 : 0)

            guard hexStr.count % 2 == 0 else { return nil }

            var newData = Data(capacity: hexStr.count/2)

            var indexIsEven = true
            for i in hexStr.indices {
                if indexIsEven {
                    let byteRange = i...hexStr.index(after: i)
                    guard let byte = UInt8(hexStr[byteRange], radix: 16) else { return nil }
                    newData.append(byte)
                }
                indexIsEven.toggle()
            }
            return newData
        }
    }

用法：

    "5413".data(using: .hexadecimal)
    "0x1234FF".data(using: .hexadecimal)

测试：

    extension Data {
        var bytes:[UInt8] { // fancy pretty call: myData.bytes -> [UInt8]
            return [UInt8](self)
        }

        // Could make a more optimized one~
        func hexa(prefixed isPrefixed:Bool = true) -> String {
            return self.bytes.reduce(isPrefixed ? "0x" : "") { $0 + String(format: "%02X", $1) }
        }
    }

    print("000204ff5400".data(using: .hexadecimal)?.hexa() ?? "failed") // OK
    print("0x000204ff5400".data(using: .hexadecimal)?.hexa() ?? "failed") // OK
    print("541".data(using: .hexadecimal)?.hexa() ?? "failed") // fails
    print("5413".data(using: .hexadecimal)?.hexa() ?? "failed") // OK

Answer 5

斯威夫特 5

extension Data {
    init?(hex: String) {
        guard hex.count.isMultiple(of: 2) else {
            return nil
        }
        
        let chars = hex.map { $0 }
        let bytes = stride(from: 0, to: chars.count, by: 2)
            .map { String(chars[$0]) + String(chars[$0 + 1]) }
            .compactMap { UInt8($0, radix: 16) }
        
        guard hex.count / bytes.count == 2 else { return nil }
        self.init(bytes)
    }
}

Answer 6

这是我确定的一个简单的解决方案：

extension NSData {
    public convenience init(hexString: String) {
        var index = hexString.startIndex
        var bytes: [UInt8] = []
        repeat {
            bytes.append(hexString[index...index.advancedBy(1)].withCString {
                return UInt8(strtoul($0, nil, 16))
            })

            index = index.advancedBy(2)
        } while index.distanceTo(hexString.endIndex) != 0

        self.init(bytes: &bytes, length: bytes.count)
    }
}

用法：

let data = NSData(hexString: "b8dfb080bc33fb564249e34252bf143d88fc018f")

输出：

print(data)
>>> <b8dfb080 bc33fb56 4249e342 52bf143d 88fc018f>

2016 年 6 月 29 日更新

我更新了初始化程序以处理格式错误的数据（即无效字符或奇数个字符）。

public convenience init?(hexString: String, force: Bool) {
    let characterSet = NSCharacterSet(charactersInString: "0123456789abcdefABCDEF")
    for scalar in hexString.unicodeScalars {
        if characterSet.characterIsMember(UInt16(scalar.value)) {
            hexString.append(scalar)
        }
        else if !force {
            return nil
        }
    }

    if hexString.characters.count % 2 == 1 {
        if force {
            hexString = "0" + hexString
        }
        else {
            return nil
        }
    }

    var index = hexString.startIndex
    var bytes: [UInt8] = []
    repeat {
        bytes.append(hexString[index...index.advancedBy(1)].withCString {
            return UInt8(strtoul($0, nil, 16))
            })

        index = index.advancedBy(2)
    } while index.distanceTo(hexString.endIndex) != 0

    self.init(bytes: &bytes, length: bytes.count)
}

Answer 7

这是我对使用 Swift 4 将十六进制字符串转换为数据的看法：

extension Data {
    private static let hexRegex = try! NSRegularExpression(pattern: "^([a-fA-F0-9][a-fA-F0-9])*$", options: [])

    init?(hexString: String) {
        if Data.hexRegex.matches(in: hexString, range: NSMakeRange(0, hexString.count)).isEmpty {
            return nil // does not look like a hexadecimal string
        }

        let chars = Array(hexString)

        let bytes: [UInt8] = 
            stride(from: 0, to: chars.count, by: 2)
                .map {UInt8(String([chars[$0], chars[$0+1]]), radix: 16)}
                .compactMap{$0}

        self = Data(bytes)
    }

    var hexString: String {
        return map { String(format: "%02hhx", $0) }.joined()
    }
}

（我加入了一个小功能，用于转换回我在这个答案中找到的十六进制字符串）

以下是您将如何使用它：

    let data = Data(hexString: "cafecafe")

    print(data?.hexString) // will print Optional("cafecafe")

Answer 8

另一种易于遵循并利用 swifts 内置十六进制解析的解决方案

func convertHexToBytes(_ str: String) -> Data? {
    let values = str.compactMap { $0.hexDigitValue } // map char to value of 0-15 or nil
    if values.count == str.count && values.count % 2 == 0 {
        var data = Data()
        for x in stride(from: 0, to: values.count, by: 2) {
          let byte = (values[x] << 4) + values[x+1] // concat high and low bits
          data.append(UInt8(byte))
        }
        return data
    }
    return nil
}

let good = "e01AFd"
let bad = "e0671"
let ugly = "GT40"
print("\(convertHexToBytes(good))") // Optional(3 bytes)
print("\(convertHexToBytes(bad))") // nil
print("\(convertHexToBytes(ugly))") // nil

Answer 9

该代码在Swift 3.0.2中为我工作。

extension String {
    /// Expanded encoding
    ///
    /// - bytesHexLiteral: Hex string of bytes
    /// - base64: Base64 string
    enum ExpandedEncoding {
        /// Hex string of bytes
        case bytesHexLiteral
        /// Base64 string
        case base64
    }

    /// Convert to `Data` with expanded encoding
    ///
    /// - Parameter encoding: Expanded encoding
    /// - Returns: data
    func data(using encoding: ExpandedEncoding) -> Data? {
        switch encoding {
        case .bytesHexLiteral:
            guard self.characters.count % 2 == 0 else { return nil }
            var data = Data()
            var byteLiteral = ""
            for (index, character) in self.characters.enumerated() {
                if index % 2 == 0 {
                    byteLiteral = String(character)
                } else {
                    byteLiteral.append(character)
                    guard let byte = UInt8(byteLiteral, radix: 16) else { return nil }
                    data.append(byte)
                }
            }
            return data
        case .base64:
            return Data(base64Encoded: self)
        }
    }
}

Answer 10

斯威夫特 5

支持iOS 13和iOS2 ... iOS12 。

extension String {
  var hex: Data? {
    var value = self
    var data = Data()
    
    while value.count > 0 {
      let subIndex = value.index(value.startIndex, offsetBy: 2)
      let c = String(value[..<subIndex])
      value = String(value[subIndex...])
      
      var char: UInt8
      if #available(iOS 13.0, *) {
        guard let int = Scanner(string: c).scanInt32(representation: .hexadecimal) else { return nil }
        char = UInt8(int)
      } else {
        var int: UInt32 = 0
        Scanner(string: c).scanHexInt32(&int)
        char = UInt8(int)
      }
      
      data.append(&char, count: 1)
    }
    
    return data
  }
}

Answer 11

斯威夫特 5

有一个使用正则表达式从十六进制字符串初始化Data实例的紧凑实现。 它在字符串中搜索十六进制数字并将它们组合到结果数据中，以便它可以支持不同格式的十六进制表示：

extension Data {
    private static let regex = try! NSRegularExpression(pattern: "([0-9a-fA-F]{2})", options: [])
    
    /// Create instance from string with hex numbers.
    init(from: String) {
        let range = NSRange(location: 0, length: from.utf16.count)
        let bytes = Self.regex.matches(in: from, options: [], range: range)
            .compactMap { Range($0.range(at: 1), in: from) }
            .compactMap { UInt8(from[$0], radix: 16) }
        self.init(bytes)
    }
    
    /// Hex string representation of data.
    var hex: String {
        map { String($0, radix: 16) }.joined()
    }
}

例子：

let data = Data(from: "0x11223344aabbccdd")
print(data.hex) // Prints "11223344aabbccdd"

let data2 = Data(from: "11223344aabbccdd")
print(data2.hex) // Prints "11223344aabbccdd"

let data3 = Data(from: "11223344 aabbccdd")
print(data3.hex) // Prints "11223344aabbccdd"

let data4 = Data(from: "11223344 AABBCCDD")
print(data4.hex) // Prints "11223344aabbccdd"

let data5 = Data(from: "Hex: 0x11223344AABBCCDD")
print(data5.hex) // Prints "11223344aabbccdd"

let data6 = Data(from: "word[0]=11223344 word[1]=AABBCCDD")
print(data6.hex) // Prints "11223344aabbccdd"

let data7 = Data(from: "No hex")
print(data7.hex) // Prints ""

Answer 12

• 处理前缀
• 忽略无效字符和不完整字节
• 使用 Swift 内置十六进制字符解析
• 不使用下标

extension Data {
    init(hexString: String) {
        self = hexString
            .dropFirst(hexString.hasPrefix("0x") ? 2 : 0)
            .compactMap { $0.hexDigitValue.map { UInt8($0) } }
            .reduce(into: (data: Data(capacity: hexString.count / 2), byte: nil as UInt8?)) { partialResult, nibble in
                if let p = partialResult.byte {
                    partialResult.data.append(p + nibble)
                    partialResult.byte = nil
                } else {
                    partialResult.byte = nibble << 4
                }
            }.data
    }
}

Answer 13

假设您的字符串是偶数大小，您可以使用它转换为十六进制并将其保存到数据：

斯威夫特 5.2

func hex(from string: String) -> Data {
    .init(stride(from: 0, to: string.count, by: 2).map {
        string[string.index(string.startIndex, offsetBy: $0) ... string.index(string.startIndex, offsetBy: $0 + 1)]
    }.map {
        UInt8($0, radix: 16)!
    })
}