繁体   English   中英

计算每个数字被键入多少次

[英]Counting how many times each number was typed

我试图计算循环中键入0到9之间的每个数字的次数,按-1会停止循环,我可以长期使用它,而且我还必须打印键入的数字最多。 目前,我只有以下代码:

int pickedNum,counter_0=0,counter_1=0,counter_2=0,counter_3=0,counter_4=0,counter_5=0,counter_6=0,counter_7=0,counter_8=0,counter_9=0;
do{
    System.out.println("Please enter a numbr between 0-9 , -1 to exit:");
    pickedNum=s.nextInt();
    if(pickedNum==0){
        counter_0++;
    }
    if(pickedNum==1){
        counter_1++;
    }
    if(pickedNum==2){
        counter_2++;
    }
    if(pickedNum==3){
        counter_3++;
    }
    if(pickedNum==4){
        counter_4++;
    }
    if(pickedNum==5){
        counter_5++;
    }
    if(pickedNum==6){
        counter_6++;
    }
    if(pickedNum==7){
        counter_7++;
    }
    if(pickedNum==8){
        counter_8++;
    }
    if(pickedNum==9){
        counter_9++;
    }
}
while(pickedNum != -1);
System.out.printf("The number 0 appears: %d \n"
        + "The number 1 appears: %d \n"
        + "The number 2 appears: %d \n"
        + "The number 3 appears: %d \n"
        + "The number 4 appears: %d \n"
        + "The number 5 appears: %d \n"
        + "The number 6 appears: %d \n"
        + "The number 7 appears: %d \n"
        + "The number 8 appears: %d \n"
        + "The number 9 appears: %d \n", 
        counter_0,counter_1,counter_2,
        counter_3,counter_4,counter_5,
        counter_6,counter_7,counter_8,counter_9);

如您所见,它工作正常,但是我知道有一种更好的选择来执行此操作。 正如我提到的,我还需要打印最大的数字(该数字是最多的数字),而用我的编程方式将需要很长的路要走。 我想获得任何提示或注释,以改进此功能,使其更轻松,更快捷地工作。 任何笔记将被应用。

编辑:忘记提及仅使用基础知识,而不使用高级方法,数组和循环都很好。

int count[] = new int[10];
do{
    counter[pickedNum]++;
} while(pickedNum != -1);

然后在您的打印语句中使用counter [0],counter [1]等。

别忘了,您最多可以输入一个以上的数字,请看一下:

 public static void main(String[] args) throws ParseException {
    int pickedNum, highestCounter = 0;
    Scanner s = new Scanner(System.in);
    int count[] = new int[10];

    while (true) {
        System.out.println("Please enter a numbr between 0-9 , -1 to exit:");
        pickedNum = s.nextInt();
        if (pickedNum != -1) {
            count[pickedNum]++;
        } else {
            break;
        }
    }

    int index1 = 0;
    for (int i : count) {
        System.out.println("The number " + index1 + " appears : " + i);
        index1++;
    }

    // Finding the number was typed the most
    for (int counter : count) {
        if (counter > highestCounter) {
            highestCounter = counter;
        }
    }

    // In case if you have more than one number that was typed the most
    Integer[] indexes = new Integer[10];
    int index2 = 0;
    for (int counter : count) {
        if (highestCounter == counter) {
            indexes[index2] = index2;
        }
        index2++;
    }

    System.out.print("The number(s) was typed the most is/are : ");
    for (Integer i : indexes) {
        if (i != null) {
            System.out.print(i + ", ");
        }

    }
}

并输出:

在此处输入图片说明

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM