Java：计算每个数字在骰子上滚动的次数

Question

public class Die {
  public static void main(String[] args) {

    Random r = new Random();    

    int dieOne=0, dieTwo=0, dieThree=0, dieFour=0, dieFive=0, dieSix=0;

    Scanner input = new Scanner(System.in);

    System.out.println("How many times would you like the die to roll?: ");
        int numRoll = input.nextInt();  

    for (int i=0; i < numRoll; i++) {
        int rNum=r.nextInt(6)+1;

        if (rNum==1); {
            dieOne++;
        } 
        if (rNum==2); {
            dieTwo++;
        }
        if (rNum==3); {
            dieThree++;
        }
        if (rNum==4); {
            dieFour++;
        }
        if (rNum==5); {
            dieFive++;
        }
        if (rNum==6); {
            dieSix++;
        }
        System.out.println("Number:" + rNum);
    }

    System.out.println("'1' was rolled:" + dieOne + "times.");
    System.out.println("'2' was rolled:" + dieTwo + "times.");
    System.out.println("'3' was rolled:" + dieThree + "times.");
    System.out.println("'4' was rolled:" + dieFour + "times.");
    System.out.println("'5' was rolled:" + dieFive + "times.");
    System.out.println("'6' was rolled:" + dieSix + "times.");
    }
}

因此，如果我运行该程序并输入2，我将得到以下信息：

Number:6
Number:3
'1' was rolled:2times.
'2' was rolled:2times.
'3' was rolled:2times.
'4' was rolled:2times.
'5' was rolled:2times.
'6' was rolled:2times.

但是我想要的输出是这样的：

Number:6
Number:3
'1' was rolled:0times.
'2' was rolled:0times.
'3' was rolled:1times.
'4' was rolled:0times.
'5' was rolled:0times.
'6' was rolled:1times.

使用相同的方法解决此问题的方法是什么？

Answer 1

您应该在if删除那些分号

if (rNum==1) {
   dieOne++;
} 

代替

if (rNum==1); {
   dieOne++;
} 

另外，您应该使用else分支或更好地使用数组来解决此类问题