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[英]display the difference in Days, Hours, Minutes and Seconds with it then updating in realtime?
[英]Getting the difference between two Dates (months/days/hours/minutes/seconds) in Swift
我正在尝试获取当前日期作为NSDate()
和来自 PHP time();
例如调用: NSDate(timeIntervalSinceReferenceDate: 1417147270)
。 我 go 如何获得两个日期之间的时间差。 我想要一个 function 来比较两个日期, if(seconds > 60)
然后返回分钟, if(minutes > 60)
返回小时数, if(hours > 24)
返回天数等等。
我应该怎么go一下这个?
编辑:当前接受的答案正是我想做的。 我推荐它以便于使用 PHP time()
function 使用的形式获取两个日期之间的时间。 如果您不是特别熟悉 PHP,那是从 1970 年 1 月 1 日开始的以秒为单位的时间。这对于 PHP 中的后端是有益的。如果您可能正在使用像 NodeJS 这样的后端,您可能需要考虑其他一些选项你会在下面找到。
Xcode 8.3 • Swift 3.1 或更高版本
您可以使用 Calendar 来帮助您创建一个扩展来进行日期计算,如下所示:
extension Date {
/// Returns the amount of years from another date
func years(from date: Date) -> Int {
return Calendar.current.dateComponents([.year], from: date, to: self).year ?? 0
}
/// Returns the amount of months from another date
func months(from date: Date) -> Int {
return Calendar.current.dateComponents([.month], from: date, to: self).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(from date: Date) -> Int {
return Calendar.current.dateComponents([.weekOfMonth], from: date, to: self).weekOfMonth ?? 0
}
/// Returns the amount of days from another date
func days(from date: Date) -> Int {
return Calendar.current.dateComponents([.day], from: date, to: self).day ?? 0
}
/// Returns the amount of hours from another date
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date, to: self).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(from date: Date) -> Int {
return Calendar.current.dateComponents([.minute], from: date, to: self).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(from date: Date) -> Int {
return Calendar.current.dateComponents([.second], from: date, to: self).second ?? 0
}
/// Returns the a custom time interval description from another date
func offset(from date: Date) -> String {
if years(from: date) > 0 { return "\(years(from: date))y" }
if months(from: date) > 0 { return "\(months(from: date))M" }
if weeks(from: date) > 0 { return "\(weeks(from: date))w" }
if days(from: date) > 0 { return "\(days(from: date))d" }
if hours(from: date) > 0 { return "\(hours(from: date))h" }
if minutes(from: date) > 0 { return "\(minutes(from: date))m" }
if seconds(from: date) > 0 { return "\(seconds(from: date))s" }
return ""
}
}
使用日期组件格式化程序
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.allowedUnits = [.second, .minute, .hour, .day, .weekOfMonth, .month, .year]
dateComponentsFormatter.maximumUnitCount = 1
dateComponentsFormatter.unitsStyle = .full
dateComponentsFormatter.string(from: Date(), to: Date(timeIntervalSinceNow: 4000000)) // "1 month"
let date1 = DateComponents(calendar: .current, year: 2014, month: 11, day: 28, hour: 5, minute: 9).date!
let date2 = DateComponents(calendar: .current, year: 2015, month: 8, day: 28, hour: 5, minute: 9).date!
let years = date2.years(from: date1) // 0
let months = date2.months(from: date1) // 9
let weeks = date2.weeks(from: date1) // 39
let days = date2.days(from: date1) // 273
let hours = date2.hours(from: date1) // 6,553
let minutes = date2.minutes(from: date1) // 393,180
let seconds = date2.seconds(from: date1) // 23,590,800
let timeOffset = date2.offset(from: date1) // "9M"
let date3 = DateComponents(calendar: .current, year: 2014, month: 11, day: 28, hour: 5, minute: 9).date!
let date4 = DateComponents(calendar: .current, year: 2015, month: 11, day: 28, hour: 5, minute: 9).date!
let timeOffset2 = date4.offset(from: date3) // "1y"
let date5 = DateComponents(calendar: .current, year: 2017, month: 4, day: 28).date!
let now = Date()
let timeOffset3 = now.offset(from: date5) // "1w"
如果有人需要显示所有时间单位,例如“小时分秒”而不仅仅是“小时”。 假设两个日期之间的时差是 1 小时 59 分 20 秒。 此功能将显示“1h 59m 20s”。
这是我的 Objective-C 代码:
extension NSDate {
func offsetFrom(date: NSDate) -> String {
let dayHourMinuteSecond: NSCalendarUnit = [.Day, .Hour, .Minute, .Second]
let difference = NSCalendar.currentCalendar().components(dayHourMinuteSecond, fromDate: date, toDate: self, options: [])
let seconds = "\(difference.second)s"
let minutes = "\(difference.minute)m" + " " + seconds
let hours = "\(difference.hour)h" + " " + minutes
let days = "\(difference.day)d" + " " + hours
if difference.day > 0 { return days }
if difference.hour > 0 { return hours }
if difference.minute > 0 { return minutes }
if difference.second > 0 { return seconds }
return ""
}
}
在 Swift 3+ 中:
extension Date {
func offsetFrom(date: Date) -> String {
let dayHourMinuteSecond: Set<Calendar.Component> = [.day, .hour, .minute, .second]
let difference = NSCalendar.current.dateComponents(dayHourMinuteSecond, from: date, to: self)
let seconds = "\(difference.second ?? 0)s"
let minutes = "\(difference.minute ?? 0)m" + " " + seconds
let hours = "\(difference.hour ?? 0)h" + " " + minutes
let days = "\(difference.day ?? 0)d" + " " + hours
if let day = difference.day, day > 0 { return days }
if let hour = difference.hour, hour > 0 { return hours }
if let minute = difference.minute, minute > 0 { return minutes }
if let second = difference.second, second > 0 { return seconds }
return ""
}
}
你问:
我想要一个函数来比较两个日期和 if(seconds > 60) 然后它返回分钟, if(minutes > 60) return hours 和 if(hours > 24) return days 等等。
我假设您正在尝试构建两个日期之间经过时间的字符串表示形式。 与其编写自己的代码来做到这一点,Apple 已经有一个专为做到这一点而设计的类。 即,使用DateComponentsFormatter
,将allowedUnits
设置为对您的应用程序有意义的任何值,将unitsStyle
设置为您想要的任何值(例如.full
),然后调用string(from:to:)
。
例如在 Swift 3 中:
let previousDate = ...
let now = Date()
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .full
formatter.allowedUnits = [.month, .day, .hour, .minute, .second]
formatter.maximumUnitCount = 2 // often, you don't care about seconds if the elapsed time is in months, so you'll set max unit to whatever is appropriate in your case
let string = formatter.string(from: previousDate, to: now)
这也将本地化适合相关设备的字符串。
或者,在 Swift 2.3 中:
let previousDate = ...
let now = NSDate()
let formatter = NSDateComponentsFormatter()
formatter.unitsStyle = .Full
formatter.allowedUnits = [.Month, .Day, .Hour, .Minute, .Second]
formatter.maximumUnitCount = 2
let string = formatter.stringFromDate(previousDate, toDate: now)
如果您正在寻找实际的数值,只需使用dateComponents
。 例如在 Swift 3 中:
let components = Calendar.current.dateComponents([.month, .day, .hour, .minute, .second], from: previousDate, to: now)
或者,在 Swift 2.3 中:
let components = NSCalendar.currentCalendar().components([.Month, .Day, .Hour, .Minute, .Second], fromDate: previousDate, toDate: now, options: [])
您可以使用 Apple 在 iOS 13 中引入的RelativeDateFormatter 。
let exampleDate = Date().addingTimeInterval(-15000)
let formatter = RelativeDateTimeFormatter()
formatter.unitsStyle = .full
let relativeDate = formatter.localizedString(for: exampleDate, relativeTo: Date())
print(relativeDate) // 4 hours ago
来自@leo-dabus 的答案的组合扩展 + DateComponentsFormatter
Xcode 8.3 • Swift 3.1
extension DateComponentsFormatter {
func difference(from fromDate: Date, to toDate: Date) -> String? {
self.allowedUnits = [.year,.month,.weekOfMonth,.day]
self.maximumUnitCount = 1
self.unitsStyle = .full
return self.string(from: fromDate, to: toDate)
}
}
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.difference(from: Date(), to: Date(timeIntervalSinceNow: 4000000)) // "1 month"
--> 使用它来查找Swift 中两个日期之间的时间间隔(使用两个字符串)。
func timeGapBetweenDates(previousDate : String,currentDate : String)
{
let dateString1 = previousDate
let dateString2 = currentDate
let Dateformatter = DateFormatter()
Dateformatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let date1 = Dateformatter.date(from: dateString1)
let date2 = Dateformatter.date(from: dateString2)
let distanceBetweenDates: TimeInterval? = date2?.timeIntervalSince(date1!)
let secondsInAnHour: Double = 3600
let minsInAnHour: Double = 60
let secondsInDays: Double = 86400
let secondsInWeek: Double = 604800
let secondsInMonths : Double = 2592000
let secondsInYears : Double = 31104000
let minBetweenDates = Int((distanceBetweenDates! / minsInAnHour))
let hoursBetweenDates = Int((distanceBetweenDates! / secondsInAnHour))
let daysBetweenDates = Int((distanceBetweenDates! / secondsInDays))
let weekBetweenDates = Int((distanceBetweenDates! / secondsInWeek))
let monthsbetweenDates = Int((distanceBetweenDates! / secondsInMonths))
let yearbetweenDates = Int((distanceBetweenDates! / secondsInYears))
let secbetweenDates = Int(distanceBetweenDates!)
if yearbetweenDates > 0
{
print(yearbetweenDates,"years")//0 years
}
else if monthsbetweenDates > 0
{
print(monthsbetweenDates,"months")//0 months
}
else if weekBetweenDates > 0
{
print(weekBetweenDates,"weeks")//0 weeks
}
else if daysBetweenDates > 0
{
print(daysBetweenDates,"days")//5 days
}
else if hoursBetweenDates > 0
{
print(hoursBetweenDates,"hours")//120 hours
}
else if minBetweenDates > 0
{
print(minBetweenDates,"minutes")//7200 minutes
}
else if secbetweenDates > 0
{
print(secbetweenDates,"seconds")//seconds
}
}
func dateDiff(dateStr:String) -> String {
var f:NSDateFormatter = NSDateFormatter()
f.timeZone = NSTimeZone.localTimeZone()
f.dateFormat = "yyyy-M-dd'T'HH:mm:ss.SSSZZZ"
var now = f.stringFromDate(NSDate())
var startDate = f.dateFromString(dateStr)
var endDate = f.dateFromString(now)
var calendar: NSCalendar = NSCalendar.currentCalendar()
let calendarUnits = NSCalendarUnit.CalendarUnitWeekOfMonth | NSCalendarUnit.CalendarUnitDay | NSCalendarUnit.CalendarUnitHour | NSCalendarUnit.CalendarUnitMinute | NSCalendarUnit.CalendarUnitSecond
let dateComponents = calendar.components(calendarUnits, fromDate: startDate!, toDate: endDate!, options: nil)
let weeks = abs(dateComponents.weekOfMonth)
let days = abs(dateComponents.day)
let hours = abs(dateComponents.hour)
let min = abs(dateComponents.minute)
let sec = abs(dateComponents.second)
var timeAgo = ""
if (sec > 0){
if (sec > 1) {
timeAgo = "\(sec) Seconds Ago"
} else {
timeAgo = "\(sec) Second Ago"
}
}
if (min > 0){
if (min > 1) {
timeAgo = "\(min) Minutes Ago"
} else {
timeAgo = "\(min) Minute Ago"
}
}
if(hours > 0){
if (hours > 1) {
timeAgo = "\(hours) Hours Ago"
} else {
timeAgo = "\(hours) Hour Ago"
}
}
if (days > 0) {
if (days > 1) {
timeAgo = "\(days) Days Ago"
} else {
timeAgo = "\(days) Day Ago"
}
}
if(weeks > 0){
if (weeks > 1) {
timeAgo = "\(weeks) Weeks Ago"
} else {
timeAgo = "\(weeks) Week Ago"
}
}
print("timeAgo is===> \(timeAgo)")
return timeAgo;
}
对Swift 3.0稍加修改的代码
let calendar = NSCalendar.current as NSCalendar
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDay(for: startDateTime)
let date2 = calendar.startOfDay(for: endDateTime)
let flags = NSCalendar.Unit.day
let components = calendar.components(flags, from: date1, to: date2, options: [])
return components.day!
我在 Leo Dabus 的 asnwer 中添加了一个“长”版本,以防您想要一个字符串,上面写着“2周前”而不是“2w”……
extension Date {
/// Returns the amount of years from another date
func years(from date: Date) -> Int {
return Calendar.current.dateComponents([.year], from: date, to: self).year ?? 0
}
/// Returns the amount of months from another date
func months(from date: Date) -> Int {
return Calendar.current.dateComponents([.month], from: date, to: self).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(from date: Date) -> Int {
return Calendar.current.dateComponents([.weekOfYear], from: date, to: self).weekOfYear ?? 0
}
/// Returns the amount of days from another date
func days(from date: Date) -> Int {
return Calendar.current.dateComponents([.day], from: date, to: self).day ?? 0
}
/// Returns the amount of hours from another date
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date, to: self).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(from date: Date) -> Int {
return Calendar.current.dateComponents([.minute], from: date, to: self).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(from date: Date) -> Int {
return Calendar.current.dateComponents([.second], from: date, to: self).second ?? 0
}
/// Returns the a custom time interval description from another date
func offset(from date: Date) -> String {
if years(from: date) > 0 { return "\(years(from: date))y" }
if months(from: date) > 0 { return "\(months(from: date))M" }
if weeks(from: date) > 0 { return "\(weeks(from: date))w" }
if days(from: date) > 0 { return "\(days(from: date))d" }
if hours(from: date) > 0 { return "\(hours(from: date))h" }
if minutes(from: date) > 0 { return "\(minutes(from: date))m" }
if seconds(from: date) > 0 { return "\(seconds(from: date))s" }
return ""
}
func offsetLong(from date: Date) -> String {
if years(from: date) > 0 { return years(from: date) > 1 ? "\(years(from: date)) years ago" : "\(years(from: date)) year ago" }
if months(from: date) > 0 { return months(from: date) > 1 ? "\(months(from: date)) months ago" : "\(months(from: date)) month ago" }
if weeks(from: date) > 0 { return weeks(from: date) > 1 ? "\(weeks(from: date)) weeks ago" : "\(weeks(from: date)) week ago" }
if days(from: date) > 0 { return days(from: date) > 1 ? "\(days(from: date)) days ago" : "\(days(from: date)) day ago" }
if hours(from: date) > 0 { return hours(from: date) > 1 ? "\(hours(from: date)) hours ago" : "\(hours(from: date)) hour ago" }
if minutes(from: date) > 0 { return minutes(from: date) > 1 ? "\(minutes(from: date)) minutes ago" : "\(minutes(from: date)) minute ago" }
if seconds(from: date) > 0 { return seconds(from: date) > 1 ? "\(seconds(from: date)) seconds ago" : "\(seconds(from: date)) second ago" }
return ""
}
}
如果您的目的是获取两个日期之间的确切天数,您可以像这样解决这个问题:
// Assuming that firstDate and secondDate are defined
// ...
var calendar: NSCalendar = NSCalendar.currentCalendar()
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDayForDate(firstDate)
let date2 = calendar.startOfDayForDate(secondDate)
let flags = NSCalendarUnit.DayCalendarUnit
let components = calendar.components(flags, fromDate: date1, toDate: date2, options: nil)
components.day // This will return the number of day(s) between dates
使用 Swift 3,您可以根据需要,选择以下两种方式之一来解决您的问题。
您可以使用DateComponentsFormatter
为您的应用程序界面创建字符串。 DateComponentsFormatter
有一个带有以下声明的maximumUnitCount
属性:
var maximumUnitCount: Int { get set }
使用此属性来限制结果字符串中显示的单位数。 例如,将此属性设置为 2,而不是“1h 10m, 30s”,结果字符串将为“1h 10m”。 当您受空间限制或想要将值向上舍入到最接近的大单位时使用此属性。
通过将maximumUnitCount
的值设置为1
,您可以保证仅以一个DateComponentsFormatter
的单位(年、月、日、小时或分钟)显示差异。
下面的 Playground 代码显示了如何显示两个日期之间的差异:
import Foundation
let oldDate = Date(timeIntervalSinceReferenceDate: -16200)
let newDate = Date(timeIntervalSinceReferenceDate: 0)
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.allowedUnits = [NSCalendar.Unit.year, .month, .day, .hour, .minute]
dateComponentsFormatter.maximumUnitCount = 1
dateComponentsFormatter.unitsStyle = DateComponentsFormatter.UnitsStyle.full
let timeDifference = dateComponentsFormatter.string(from: oldDate, to: newDate)
print(String(reflecting: timeDifference)) // prints Optional("5 hours")
请注意DateComponentsFormatter
对结果进行四舍五入。 因此, 4 小时 30 分钟的差异将显示为5 hours 。
如果你需要重复这个操作,你可以重构你的代码:
import Foundation
struct Formatters {
static let dateComponentsFormatter: DateComponentsFormatter = {
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.allowedUnits = [NSCalendar.Unit.year, .month, .day, .hour, .minute]
dateComponentsFormatter.maximumUnitCount = 1
dateComponentsFormatter.unitsStyle = DateComponentsFormatter.UnitsStyle.full
return dateComponentsFormatter
}()
}
extension Date {
func offset(from: Date) -> String? {
return Formatters.dateComponentsFormatter.string(from: oldDate, to: self)
}
}
let oldDate = Date(timeIntervalSinceReferenceDate: -16200)
let newDate = Date(timeIntervalSinceReferenceDate: 0)
let timeDifference = newDate.offset(from: oldDate)
print(String(reflecting: timeDifference)) // prints Optional("5 hours")
如果您不需要向用户显示两个日期之间的差异的格式,则可以使用Calendar
。 Calendar
有一个dateComponents(_:from:to:)
,它具有以下声明:
func dateComponents(_ components: Set<Calendar.Component>, from start: Date, to end: Date) -> DateComponents
返回两个日期之间的差值。
下面使用dateComponents(_:from:to:)
的 Playground 代码显示了如何通过仅返回一种Calendar.Component
类型(年、月、日、小时或分钟)的差异来检索两个日期之间的差异。
import Foundation
let oldDate = Date(timeIntervalSinceReferenceDate: -16200)
let newDate = Date(timeIntervalSinceReferenceDate: 0)
let descendingOrderedComponents = [Calendar.Component.year, .month, .day, .hour, .minute]
let dateComponents = Calendar.current.dateComponents(Set(descendingOrderedComponents), from: oldDate, to: newDate)
let arrayOfTuples = descendingOrderedComponents.map { ($0, dateComponents.value(for: $0)) }
for (component, value) in arrayOfTuples {
if let value = value, value > 0 {
print(component, value) // prints hour 4
break
}
}
如果你需要重复这个操作,你可以重构你的代码:
import Foundation
extension Date {
func offset(from: Date) -> (Calendar.Component, Int)? {
let descendingOrderedComponents = [Calendar.Component.year, .month, .day, .hour, .minute]
let dateComponents = Calendar.current.dateComponents(Set(descendingOrderedComponents), from: from, to: self)
let arrayOfTuples = descendingOrderedComponents.map { ($0, dateComponents.value(for: $0)) }
for (component, value) in arrayOfTuples {
if let value = value, value > 0 {
return (component, value)
}
}
return nil
}
}
let oldDate = Date(timeIntervalSinceReferenceDate: -16200)
let newDate = Date(timeIntervalSinceReferenceDate: 0)
if let (component, value) = newDate.offset(from: oldDate) {
print(component, value) // prints hour 4
}
在 Swift 2.2 中
/// Returns the amount of years from another date
func years(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Year], fromDate: fromdate, toDate: NSDate(), options: []).year ?? 0
}
/// Returns the amount of months from another date
func months(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Month], fromDate: fromdate, toDate: NSDate(), options: []).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.WeekOfYear], fromDate: fromdate, toDate: NSDate(), options: []).weekOfYear ?? 0
}
/// Returns the amount of days from another date
func days(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Day], fromDate: fromdate, toDate: NSDate(), options: []).day ?? 0
}
/// Returns the amount of hours from another date
func hours(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Hour], fromDate: fromdate, toDate: NSDate(), options: []).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Minute], fromDate: fromdate, toDate: NSDate(), options: []).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components(.Second, fromDate: fromdate, toDate: NSDate(), options: []).second ?? 0
}
Leo Dabus 的答案的一个小补充,以提供复数版本并更具人类可读性。
斯威夫特 3
extension Date {
/// Returns the amount of years from another date
func years(from date: Date) -> Int {
return Calendar.current.dateComponents([.year], from: date, to: self).year ?? 0
}
/// Returns the amount of months from another date
func months(from date: Date) -> Int {
return Calendar.current.dateComponents([.month], from: date, to: self).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(from date: Date) -> Int {
return Calendar.current.dateComponents([.weekOfMonth], from: date, to: self).weekOfMonth ?? 0
}
/// Returns the amount of days from another date
func days(from date: Date) -> Int {
return Calendar.current.dateComponents([.day], from: date, to: self).day ?? 0
}
/// Returns the amount of hours from another date
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date, to: self).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(from date: Date) -> Int {
return Calendar.current.dateComponents([.minute], from: date, to: self).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(from date: Date) -> Int {
return Calendar.current.dateComponents([.second], from: date, to: self).second ?? 0
}
/// Returns the a custom time interval description from another date
func offset(from date: Date) -> String {
if years(from: date) == 1 { return "\(years(from: date)) year" } else if years(from: date) > 1 { return "\(years(from: date)) years" }
if months(from: date) == 1 { return "\(months(from: date)) month" } else if months(from: date) > 1 { return "\(months(from: date)) month" }
if weeks(from: date) == 1 { return "\(weeks(from: date)) week" } else if weeks(from: date) > 1 { return "\(weeks(from: date)) weeks" }
if days(from: date) == 1 { return "\(days(from: date)) day" } else if days(from: date) > 1 { return "\(days(from: date)) days" }
if hours(from: date) == 1 { return "\(hours(from: date)) hour" } else if hours(from: date) > 1 { return "\(hours(from: date)) hours" }
if minutes(from: date) == 1 { return "\(minutes(from: date)) minute" } else if minutes(from: date) > 1 { return "\(minutes(from: date)) minutes" }
return ""
}
}
Swift 5
func dateDiff(dateStr:String) -> String {
let f:DateFormatter = DateFormatter()
f.timeZone = NSTimeZone.local
f.dateFormat = "yyyy-M-dd'T'HH:mm:ss.SSSZZZ"
let now = f.string(from: NSDate() as Date)
let startDate = f.date(from: dateStr)
let endDate = f.date(from: now)
var _: NSCalendar = NSCalendar.current as NSCalendar
let dateComponents = Calendar.current.dateComponents([ .weekOfMonth, .day , .hour , .minute , .second], from: startDate!, to: endDate!)
let weeks = abs(dateComponents.weekOfMonth!)
let days = abs(dateComponents.day!)
let hours = abs(dateComponents.hour!)
let min = abs(dateComponents.minute!)
let sec = abs(dateComponents.second!)
var timeAgo = ""
if (sec > 0){
if (sec > 1) {
timeAgo = "\(sec) Seconds Ago"
} else {
timeAgo = "\(sec) Second Ago"
}
}
if (min > 0){
if (min > 1) {
timeAgo = "\(min) Minutes Ago"
} else {
timeAgo = "\(min) Minute Ago"
}
}
if(hours > 0){
if (hours > 1) {
timeAgo = "\(hours) Hours Ago"
} else {
timeAgo = "\(hours) Hour Ago"
}
}
if (days > 0) {
if (days > 1) {
timeAgo = "\(days) Days Ago"
} else {
timeAgo = "\(days) Day Ago"
}
}
if(weeks > 0){
if (weeks > 1) {
timeAgo = "\(weeks) Weeks Ago"
} else {
timeAgo = "\(weeks) Week Ago"
}
}
print("timeAgo is===> \(timeAgo)")
return timeAgo;
}
这是我对上述 Swift 3 个答案的回答。 这是截至 2016 年 11 月的最新版本,Xcode 版本为 8.2 Beta (8C23)。 使用了上面 Sagar 和 Emin 的一些建议,有时不得不让 Xcode 自动完成来建议语法。 看起来这个测试版的语法真的发生了变化。 我从 DatePicker 得到的buyDate
:
let calendar = NSCalendar.current as NSCalendar
let currentDate = Date()
let date1 = calendar.startOfDay(for: buyDate!)
let date2 = calendar.startOfDay(for: currentDate)
let flags = NSCalendar.Unit.day
let components = calendar.components(flags, from: date1, to: date2)
NSLog(" day= \(components.day)")
这是较短的版本:基本上我现在尝试获取发布时间戳与Date()
之间的差异。
// MARK: - UPDATE Time Stamp
static func updateTimeStampPost(postTimeStamp: Date?, _ completion: (_ finalString: String?) -> Void) {
// date in the current state
let date = Date()
let dateComponentFormatter = DateComponentsFormatter()
// change the styling date, wether second minute or hour
dateComponentFormatter.unitsStyle = .abbreviated
dateComponentFormatter.allowedUnits = [.second, .minute, .hour, .day, .weekOfMonth]
dateComponentFormatter.maximumUnitCount = 1
// return the date new format as a string in the completion
completion(dateComponentFormatter.string(from: postTimeStamp!, to: date))
}
对于 XCode 版本 8.3.3 和 Swift 3.0:
let dateFormatter = DateFormatter()
dateFormatter.dateStyle = .medium
dateFormatter.timeStyle = .short
var beginDate = "2017-08-24 12:00:00"
var endDate = "2017-09-07 12:00:00"
let startDateTime = dateFormatter.date(from: beginDate) //according to date format your date string
print(startDateTime ?? "") //Convert String to Date
let endDateTime = dateFormatter.date(from: endDate) //according to date format your date string
print(endDateTime ?? "") //Convert String to Date
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.allowedUnits = [NSCalendar.Unit.minute,NSCalendar.Unit.hour,NSCalendar.Unit.day]
let interval = endDateTime!.timeIntervalSince(startDateTime!)
var diff = dateComponentsFormatter.string(from: interval)!
print(diff)
var day_i = 0
var hour_i = 0
var min_i = 0
if (diff.contains("d"))
{
let day = diff.substring(to: (diff.range(of: "d")?.lowerBound)!)
day_i = Int(day)!
print ("day --> \(day_i)")
diff = diff.substring(from:(diff.range(of : " ")?.upperBound )!)
print(diff)
}
let hour = diff.substring(to: (diff.range(of : ":")?.lowerBound )!)
hour_i = Int(hour)!
print ("hour --> \(hour_i)")
let min = diff.substring(from: (diff.range(of : ":")?.upperBound )!)
min_i = Int(min)!
print ("min --> \(min_i)")
jose920405 答案中的一些补充使其与Swift 3.0及更高版本兼容
func getDateTimeDiff(dateStr:String) -> String {
let formatter : DateFormatter = DateFormatter()
formatter.timeZone = NSTimeZone.local
formatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let now = formatter.string(from: NSDate() as Date)
let startDate = formatter.date(from: dateStr)
let endDate = formatter.date(from: now)
// *** create calendar object ***
var calendar = NSCalendar.current
// *** Get components using current Local & Timezone ***
print(calendar.dateComponents([.year, .month, .day, .hour, .minute, .second], from: startDate!))
// *** define calendar components to use as well Timezone to UTC ***
let unitFlags = Set<Calendar.Component>([.year, .month, .day, .hour, .minute, .second])
calendar.timeZone = TimeZone(identifier: "UTC")!
let dateComponents = calendar.dateComponents(unitFlags, from: startDate!, to: endDate!)
// *** Get Individual components from date ***
let years = dateComponents.year!
let months = dateComponents.month!
let days = dateComponents.day!
let hours = dateComponents.hour!
let minutes = dateComponents.minute!
let seconds = dateComponents.second!
var timeAgo = ""
if (seconds > 0){
if seconds < 2 {
timeAgo = "Second Ago"
}
else{
timeAgo = "\(seconds) Second Ago"
}
}
if (minutes > 0){
if minutes < 2 {
timeAgo = "Minute Ago"
}
else{
timeAgo = "\(minutes) Minutes Ago"
}
}
if(hours > 0){
if hours < 2 {
timeAgo = "Hour Ago"
}
else{
timeAgo = "\(hours) Hours Ago"
}
}
if (days > 0) {
if days < 2 {
timeAgo = "Day Ago"
}
else{
timeAgo = "\(days) Days Ago"
}
}
if(months > 0){
if months < 2 {
timeAgo = "Month Ago"
}
else{
timeAgo = "\(months) Months Ago"
}
}
if(years > 0){
if years < 2 {
timeAgo = "Year Ago"
}
else{
timeAgo = "\(years) Years Ago"
}
}
DLog("timeAgo is ===> \(timeAgo)")
return timeAgo;
}
使用此代码:
let registrationDateString = "2008-10-06 00:00:00"
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd hh:mm:ss"
if let registrationDate = dateFormatter.date(from: registrationDateString) {
let currentDate = Date()
let dateDifference = Calendar.current.dateComponents([.day, .month, .year],
from: registrationDate,
to: currentDate)
print("--------------------- Result: \(dateDifference.year ?? 0) years \(dateDifference.month ?? 0) months and \(dateDifference.day ?? 0) days")
} else {
print("--------------------- No result")
}
输出为: 结果:10 年 1 个月零 18 天
import Foundation
extension DateComponents {
func dateComponentsToTimeString() -> String {
var hour = "\(self.hour!)"
var minute = "\(self.minute!)"
var second = "\(self.second!)"
if self.hour! < 10 { hour = "0" + hour }
if self.minute! < 10 { minute = "0" + minute }
if self.second! < 10 { second = "0" + second }
let str = "\(hour):\(minute):\(second)"
return str
}
}
extension Date {
func offset(from date: Date)-> DateComponents {
let components = Set<Calendar.Component>([.second, .minute, .hour, .day, .month, .year])
let differenceOfDate = Calendar.current.dateComponents(components, from: date, to: self)
return differenceOfDate
}
}
用:
var durationString: String {
return self.endTime.offset(from: self.startTime).dateComponentsToTimeString()
}
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