将2个字母值加在一起？

Question

我目前正在尝试使用关键字进行加密。 我已经接受了用户输入和关键字输入，并获得了字母中每个字母的值。 （a = 1，b = 2，c = 3等），现在我需要将这两个值加在一起。 由于我在代码中使用了while循环来获取每个字母并获取值，因此我无法获取每个单独的值并进行添加。 有人可以就正确添加每个值的正确方向给我点意见吗？ 谢谢。

def keyEnc():
    alpha = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
    gcselist = ['g','c','s','e']
    code = input("Please enter the word you would like to encrypt: ")
    print("User's word is " + code)
    print("The number of letters in the code is: ")
    print(len(code))
    x=0
    while x < len(code):
        currLetterA=code[x]
        print("Letter: ",currLetterA)
        myii=alpha.index(currLetterA)
        myii=myii+1
        print("The Value Is: ",myii)
        x=x+1
#############################################################################################
    key = input("Please enter the keyword you would like to encrypt your word by: ")
    x=0
    while x < len(key):
        currLetter=key[x]
        print("Letter: ",currLetter)
        myi=alpha.index(currLetter)
        myi=myi+1
        print("The Value Is: ",myi)
        finWord = myi+myii
        print(finWord)
        x=x+1
keyEnc()

Answer 1

听起来您正在尝试执行以下操作：

cleartext:  somewords = 19 15 13  5 23 15 18  4 19
key:        something = 19 15 13  5 20  8  9 14  7
                       ++++++++++++++++++++++++++++
ciphertext:             38 30 26 10 43 23 27 18 26

那正确吗？ 在这种情况下，您将需要一个数字列表，而不仅仅是一个输出。 另请注意，如果您的明文和密钥长度不完全相同，则此方法将无效。 想像：

cleartext:  somewords = 19 15 13  5 23 15 18  4 19
key:        banana    =  2  1 14  1 14  1
                       ++++++++++++++++++++++++++++
ciphertext:             21 16 27  6 37 16  ?  ?  ?

要么

cleartext:  somewords     = 19 15 13  5 23 15 18  4 19
key:        bananahammock =  2  1 14  1 14  1  8  1 13 13 15  3 11
                           ++++++++++++++++++++++++++++++++++++++++
ciphertext:                 21 16 27  6 37 16 36  5 32  ?  ?  ?  ?

但是，在这种情况下，您似乎需要这样做：

def key_enc():
    cleartext_word = input("Enter the word you want to encrypt: ")
    key = input("Enter the word you want as a key: ")
    if len(cleartext_word) != len(key):
        # I'm not sure how to handle this, so that's your design decision
        # but possibly just:
        raise ValueError("Clear text and key must have equal length")
    result = list()
    def lookup_letter(letter):
        """Helper function to return a proper index.

        a = 1, b = 2, c = 3, ..."""

        return ord(letter) - 96

    for letter, key_letter in zip(cleartext_word, key):
        result.append(lookup_letter(letter) + lookup_letter(key_letter))

    return result

这里缺少zip的使用是您丢失的关键。 从技术上讲，您不需要这样做，您可以像执行代码一样使用while循环，方法是：

def key_enc():
    # prompt for the cleartext_word and key as above
    result = []
    i = 0
    while i < len(cleartext_word): # which MUST BE EQUAL TO len(key)
        clear_letter = cleartext_word[i]
        key_letter = key[i]
        result_letter = ord(clear_letter)-96 + ord(key_letter)-96
        result.append(result_letter)

但是用这种方式很难理解。

说到难以阅读，基本上您的整个功能是：

result = list(map(lambda letters: sum(map(ord,letters))-192, zip(cleartext_word, key_word)))
# YUCK!!!