如何在Python中将元组分配给字典键？

Question

我有这样的数据：

(asn,prefix,ip,count_domain)
(15967, '77.55.0.0/16', '77.55.236.177', 10)
(15967, '77.55.0.0/16', '77.55.236.178', 11)
(20773, '195.225.104.0/22', '195.225.104.182', 22)
(20773, '195.225.104.0/22', '195.225.104.181', 10)
(8560, '87.106.0.0/16', '87.106.1.10', 15)
(20454, '198.24.128.0/19', '198.24.143.43', 89)
(20454, '198.24.128.0/19', '198.24.143.45', 608)
(20454, '198.24.128.0/19', '198.24.143.46', 32)
(31815, '216.70.96.0/20', '216.70.102.229', 12)
(31815, '216.70.96.0/20', '216.70.102.228', 20)

我想提取每个asn和前缀的一些IP和域，如下所示：

(asn,prefix,count_ip,count_domain)
(15967, '77.55.0.0/16', 2, 21)
(20773, '195.225.104.0/22', 2, 32)
(8560, '87.106.0.0/16', 1, 15)
(20454, '198.24.128.0/19', 3, 729)
(31815, '216.70.96.0/20', 2, 32)

我当前的python脚本是这个，但是字典中语法错误导致我出错。 有人可以帮忙吗？

count = {}

with open (output,'w') as w:
    with open (file , 'r') as f:
        for line in f :
            if line.strip() != '':
                domain = int(line.split('|')[1])
                if  domain>=10:
                    ip = line.split('|')[0]
                    try:
                        prefix = asndb.lookup(ip)[1]
                        asn = asndb.lookup(ip)[0]
                        if [asn,prefix] not in count:
                            count[asn,prefix] = count
                        else:
                            count[asn,prefix] += count
#                        print(asn,prefix,ip,domain)
                    except:
                        print line
                        pass

错误：

    if asn,prefix not in count:
          ^
SyntaxError: invalid syntax

Answer 1

使用asn和prefix的值显式分配一个元组，然后使用该元组作为键（我认为这是根据标题您要执行的操作）。 另外，如果您以我认为的使用方式使用字典，请将计数增加1（而不是尝试将对字典的引用分配为值）。

                    prefix = asndb.lookup(ip)[1]
                    asn = asndb.lookup(ip)[0]
                    key = (asn, prefix)
                    if key not in count:
                        count[key] = 1
                    else:
                        count[key] += 1

编辑以修复由@AshwiniChaudhary捕获的愚蠢错字

Answer 2

if [asn,prefix] not in count:

列表类型不能成为字典的键。