[英]AES CTR symmetric encryption and decryption
我不是openssl的专家。 我已经将以下代码放在一起使用AES-CTR加密和解密邮件。 输出不是我期望看到的。
#include "stdafx.h"
#include <openssl/aes.h>
#include <openssl/evp.h>
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
#include <tchar.h>
#include <psapi.h>
#include <openssl/rand.h> //for RAND_bytes function
struct ctr_state {
unsigned char ivec[16]; /* ivec[0..7] is the IV, ivec[8..15] is the big-endian counter */
unsigned int num;
unsigned char ecount[16];
};
int init_ctr(struct ctr_state *state, const unsigned char iv[8])
{
/* aes_ctr128_encrypt requires 'num' and 'ecount' set to zero on the
* first call. */
state->num = 0;
memset(state->ecount, 0, 16);
/* Initialise counter in 'ivec' to 0 */
memset(state->ivec + 8, 0, 8);
/* Copy IV into 'ivec' */
memcpy(state->ivec, iv, 8);
return(0);
}
int main(int argc, char **argv)
{
unsigned char key[] = "thiskeyisverybad"; // It is 128bits though..
unsigned char iv[8];
struct ctr_state state;
if (!RAND_bytes(iv, 8))
printf("\nError in RAND_Bytes...\n");
init_ctr(&state, iv);
AES_KEY aes_key;
AES_set_encrypt_key(key, 128, &aes_key);
char msg[] = "hey";
unsigned char cipher[AES_BLOCK_SIZE];
char plain[AES_BLOCK_SIZE];
AES_ctr128_encrypt((unsigned char *) msg, cipher, AES_BLOCK_SIZE, &aes_key, state.ivec, state.ecount, &state.num);
AES_ctr128_encrypt(cipher, (unsigned char *) plain, AES_BLOCK_SIZE, &aes_key, state.ivec, state.ecount, &state.num);
printf("\nPLAIN:%s\n", plain);
return 0;
}
我得到的结果是这样的:“PLAIN:¢u∩U└■My&nu9♫_╠╠╠╠╠╠╠╠”Åä▬♂☻e0Tç§▓→♀v╠╠╠╠╠╠╠╠嘿”
知道是什么原因引起的吗? 我想要做的就是使用点击率来加密和解密消息。 我想获得与明文(或+1字节)相同的加密长度。 我用DES做了这个,但DES并不安全。 然后,我将使用AES-CTR加密和解密我的网络流量(流)。
您需要在解密前重置:
…
init_ctr(&state, iv);
AES_ctr128_encrypt(
cipher,
(unsigned char *) plain,
AES_BLOCK_SIZE,
&aes_key,
state.ivec,
state.ecount,
&state.num
);
printf("\nPLAIN:%s\n", plain);
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