在Python列表中打印最匹配的列表，其中每个元素都在内部分开

Question

我创建基于在一个文件中，即元件，当元件Python列表row[0]存在于row[3]附加两排列出'matches' ，反之亦然，当元素row[3]是在row[0] ，将它们附加到'matches' 。 列表如下所示

['Peripheral Blood Mononuclear Cells;peripheral blood mononuclear cells', 'Blood;peripheral blood mononuclear cells', 'Hispanic or Latino;hispanic', 'Black;black', 'Black;black', 'Asian;asian', 'Asian;asian', 'Asian;caucasian', 'caucasian;caucasian', 'caucasian;caucasian', 'Seizures;seizures', 'Seizure;seizures', 'Seizures;seizures', 'Seizures;seizures', 'Abscess;abscess']

我只想为每个元素或完全匹配打印第一个输出，而不管以下情况如何：

['Peripheral Blood Mononuclear Cells;peripheral blood mononuclear', 'Hispanic or Latino;hispanic', 'Black;black', 'Asian;asian', 'caucasian;caucasian', 'Seizures;seizures', 'Abscess;abscess']

在这里，如果您注意到，列表的每个元素都由";"分隔";" 。 我试图以此为标准进行比较。 我只希望每个元素的第一个出现是基于";"之后的一个或多个单词 或者，当双方的单词都相同时。 例如，对于外周血单个核细胞，它选择了第一次出现，而对于白种人，则选择了第二个出现，因为它是完美的匹配。 我真的很感谢在投票之前的任何帮助。

Answer 1

您需要跟踪看到的所有完整字符串和拆分的子字符串，只添加我们未看到的内容即可：

l=['Peripheral Blood Mononuclear Cells;peripheral blood mononuclear cells', 'Blood;peripheral blood mononuclear cells', 'Hispanic or Latino;hispanic', 'Black;black', 'Black;black', 'Asian;asian', 'Asian;asian', 'Asian;caucasian', 'caucasian;caucasian', 'caucasian;caucasian', 'Seizures;seizures', 'Seizure;seizures', 'Seizures;seizures', 'Seizures;seizures', 'Abscess;abscess']
seen = set()
res = []
for ele in l:
    a,b = ele.split(";",1)
    # make sure we don't have not seen the full string nor left/right hand substring
    # or we find exact matches both sides and we don't already have that perfect match added
    if ele.lower() not in seen and not any(x.lower() in seen for x in (a,b)) or a == b and ele not in seen:
        res.append(ele)
    # keep track of all full strings and left/right substrings 
    seen.update([a.lower(),b.lower(),ele.lower()])
print(res)
['Peripheral Blood Mononuclear Cells;peripheral blood mononuclear cells', 'Hispanic or Latino;hispanic', 'Black;black', 'Asian;asian', 'caucasian;caucasian', 'Seizures;seizures', 'Abscess;abscess']