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[英]Replace column value based on value in other column, for all rows in a pandas dataframe
[英]Pandas DataFrame, replace value of a column by the value of an other column
我的boosting_df Pandas DataFrame如下:
sku boost1 boost2 boost3 boost4
0 a ffffdfg a fggg replace
1 b fff fff fff replace
2 c ddf b ddf replace
3 d dfgd dfgd d replace
对于每一行,如果'sku'的值与值boost1或boost2或boost3相同,那么我想用匹配值替换boost4内的值
例:
sku boost1 boost2 boost3
0 a ffffdfg replace fggg
1 b fff fff fff
2 c ddf b ddf
3 d dfgd dfgd replace
我试过了:
boosting_df.loc[boosting_df['boost1'] == boosting_df['sku'], 'boost1'] = boosting_df['boost4']
boosting_df.loc[boosting_df['boost2'] == boosting_df['sku'], 'boost2'] = boosting_df['boost4']
boosting_df.loc[boosting_df['boost2'] == boosting_df['sku'], 'boost3'] = boosting_df['boost4']
但是我收到以下错误:
ValueError: shape mismatch: value array of shape (4,) could not be broadcast to indexing result of shape (0,)
每个布尔掩码必须应用于赋值的两侧,以便维度和索引匹配:
for i in range(1, 4):
col = 'boost{}'.format(i)
mask = (df['sku'] == df[col])
df.loc[mask, col] = df.loc[mask, 'boost4']
输出:
sku boost1 boost2 boost3 boost4
0 a ffffdfg replace fggg replace
1 b fff fff fff replace
2 c ddf b ddf replace
3 d dfgd dfgd replace replace
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