Python搜索两个词正则表达式

Question

我试图找出一个句子中是否包含短语“ go * to”，例如“ go to to”，“ go up to”等。我正在使用Textblob，我知道我可以在下面使用它：

search_go_to = set(["go", "to"])
go_to_blob = TextBlob(var)
matches = [str(s) for s in go_to_blob.sentences if search_go_to & set(s.words)]
print(matches)

但这也将返回诸如“不要去那里并将其带给他”之类的句子，我不希望这样。 有谁知道我该怎么做，例如text.find（“ go * to”）？

Answer 1

尝试使用：

for match in re.finditer(r"go\s+\w+\s+to", text, re.IGNORECASE):

Answer 2

使用generator expressions

>>> search_go_to = set(["go", "to"])
>>> m = ' .*? '.join(x for x in search_go_to)
>>> words = set(["go over to", "go up to", "foo bar"])
>>> matches = [s for s in words if re.search(m, s)]
>>> print(matches)
['go over to', 'go up to']

Answer 3

尝试这个

text = "something go over to something"

if re.search("go\s+?\S+?\s+?to",text):
    print "found"
else:
    print "not found"

正则表达式：-

\s is for any space
\S is for any non space including special characters
+? is for no greedy approach (not required in OP's question)

因此re.search("go\\s+?\\S+?\\s+?to",text)将匹配"something go W#$%^^$ to something" ，当然，这也"something go over to something"

Answer 4

这样行吗？

import re
search_go_to = re.compile("^go.*to$")
go_to_blob = TextBlob(var)
matches = [str(s) for s in go_to_blob.sentences if search_go_to.match(str(s))]
print(matches)

正则表达式的说明：

^    beginning of line/string
go   literal matching of "go"
.*   zero or more characters of any kind
to   literal matching of "to"
$    end of line/string

如果你不想“要”来匹配，插入\\\\b之前（字边界） to后go 。