第二个while循环仅循环一次

Question

我正在做石头剪刀布游戏。 一切正常，除了我不明白为什么第二个while循环在此代码中不起作用。 我想制作程序，以便如果用户未输入“ R”，“ P”或“ S”，则将被告知用户该输入无效，并提示用户再次输入答案。 它对player1完全正常，但对player2不起作用。 对于player2，如果您不输入“ R”或“ P或“ S”，则无论您输入什么内容，它都会提示您再次输入一个新值，但只能输入一次。感谢所有帮助！

if playGame == "Y":
    print("Ok, here we go.")

    player1 = input("Player1, what is your choice, R, P, or S? ")
    player1 = player1.upper()

    while player1 != 'R' and player1 != 'P' and player1 != 'S':
            player1 = input("Invalid answer.  Please answer R, P, or S: ")
            player1 = player1.upper()

    player2 = input("Player2, what is your choice, R, P, or S? ")
    player2 = player2.upper()

    while player2 != 'R' and player2 != 'P' and player2 != 'S':
            player2 = input("Invalid answer.  Please answer R, P, or S: ")
            player2 = player1.upper()

Answer 1

错误在最后一行

player2 = player1.upper()

应该

player2 = player2.upper()

Answer 2

当用户输入无效值时，使用while循环反复询问用户。

码：

playGame = raw_input("You want to play game: if yes then enter Y:").upper()
if playGame == "Y":
    print("Ok, here we go.")
    player1 = ''
    while  1:
        player1 = raw_input("Player1, what is your choice, R, P, or S?:").upper()
        if player1 not in ['R', 'P', 'S']:
            print "Invalid answer."
        else:
            break

    player2 = ''
    while 1:
        player2 = raw_input("Player2, what is your choice, R, P, or S?:").upper()       
        if player2 not in ['R', 'P', 'S']:
            print "Invalid answer."
        else:
            break

    print "player1:", player1
    print "player2:", player2

输出：

vivek@vivek:~/Desktop/stackoverflow$ python 7.py
You want to paly game: if yes then enter Y:Y
Ok, here we go.
Player1, what is your choice, R, P, or S?:a
Invalid answer.
Player1, what is your choice, R, P, or S?:R
Player2, what is your choice, R, P, or S?:w
Invalid answer.
Player2, what is your choice, R, P, or S?:q
Invalid answer.
Player2, what is your choice, R, P, or S?:s
player1: R
player2: S