带xpath的Python Selenium的select元素时出现InvalidSelectorException

Question

我有这个html片段：

<div class="btn">
    <a href="javascript:void(0)" class="S_btn_b" node-type="OK">
        <span>确定</span>
    </a>
</div>

我想选择确定元素并单击它。 我用xpath尝试了以下选择器：

confirm_btn = driver.find_element_by_xpath('//div[@class="btn"]//span[text()="确定"]')

但是程序只是抱怨说这不是一个带有此异常的有效选择器：

Traceback (most recent call last):
  File "test.py", line 63, in <module>
    ac.move_to_element(driver.find_element_by_xpath('//div[@class="btn"]/span[text()="确定"'))
  File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 230, in find_element_by_xpath
    return self.find_element(by=By.XPATH, value=xpath)
  File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 662, in find_element
    {'using': by, 'value': value})['value']
  File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 173, in execute
    self.error_handler.check_response(response)
  File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/errorhandler.py", line 166, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.InvalidSelectorException

我做错什么了吗 ？

Answer 1

如果未将XPath表达式标记为Unicode，则在将搜索命令发送到浏览器时，汉字会被弄乱，并且搜索将搜索您想要的内容以外的其他内容，因此将XPath表达式标记为Unicode：

confirm_btn = driver.find_element_by_xpath(u'//div[@class="btn"]//span[text()="确定"]')