正则表达式：逗号分割，但在括号和引号中排除逗号（单双和双）

Question

我有一个字符串

5,(5,5),C'A,B','A,B',',B','A,',"A,B",C"A,B" 

我想在逗号上拆分它，但需要在括号和引号（单引号和双引号）中排除逗号。

像这样

5 (5,5) C'A,B' 'A,B' ',B' 'A,' "A,B" C"A,B"

用java Regular Expression如何实现这个？

Answer 1

你可以使用这个正则表达式：

String input = "5,(5,5),C'A,B','A,B',',B','A,',\"A,B\",C\"A,B\"";
String[] toks = input.split( 
                ",(?=(([^']*'){2})*[^']*$)(?=(([^\"]*\"){2})*[^\"]*$)(?![^()]*\\))" );
for (String tok: toks)
    System.out.printf("<%s>%n", tok);

输出：

<5>
<(5,5)>
<C'A,B'>
<'A,B'>
<',B'>
<'A,'>
<"A,B">
<C"A,B">

说明：

,                         # Match literal comma
(?=(([^']*'){2})*[^']*$)  # Lookahead to ensure comma is followed by even number of '
(?=(([^"]*"){2})*[^"]*$)  # Lookahead to ensure comma is followed by even number of "
(?![^()]*\\))             # Negative lookahead to ensure ) is not followed by matching
                          # all non [()] characters in between

Answer 2

,(?![^(]*\))(?![^"']*["'](?:[^"']*["'][^"']*["'])*[^"']*$)

尝试这个。

见演示 。

对于java

,(?![^(]*\\))(?![^"']*["'](?:[^"']*["'][^"']*["'])*[^"']*$)

Answer 3

而不是split字符串，而是考虑匹配。

String s  = "5,(5,5),C'A,B','A,B',',B','A,',\"A,B\",C\"A,B\"";
Pattern p = Pattern.compile("(?:[^,]*(['\"])[^'\"]*\\1|\\([^)]*\\))|[^,]+");
Matcher m = p.matcher(s);
while (m.find()) {
  System.out.println(m.group());
}

产量

5
(5,5)
C'A,B'
'A,B'
',B'
'A,'
"A,B" 
C"A,B"