[英]Sorting log file into groups with bash and awk
我正在尝试以特定方式对日志文件进行排序,但是我不确定如何执行最后一步。
我的日志文件具有以下条目:
Feb 15 17:00:34 server sshd[13879]: Invalid user test from 200.242.94.133
Feb 15 17:00:35 server sshd[13780]: Invalid user ftpuser from 200.242.94.133
Feb 15 17:01:34 server sshd[13890]: Invalid user test from 200.242.94.133
Feb 15 17:01:35 server sshd[13791]: Invalid user vnc from 200.242.94.133
Feb 15 17:01:35 server sshd[13794]: Invalid user test from 50.63.172.108
Feb 15 17:01:36 server sshd[13798]: Invalid user vnc from 50.63.172.108
我使用以下命令:
cat logfile | grep "Invalid user" | awk '{print $8 ", " $10 }' | sort -t":" -k2,2 | uniq -c
哪个输出:
1 ftpuser, 200.242.94.133
2 test, 200.242.94.133
1 test, 50.63.172.108
1 vnc, 200.242.94.133
1 vnc, 50.63.172.108
我想得到:
1 ftpuser, (1) 200.242.94.133
3 test, (2) 200.242.94.133, (1) 50.63.172.108
2 vnc, (1) 200.242.94.133, (1) 50.63.172.108
我不确定如何对单词列求和,同时保持对IP地址的计数,然后将其与其他结果一起包括在内。
尝试回答:
# awk '/Invalid user/{user[$8]++;ip[$8][$10]++} END{for (u in user){printf "%s %s",user[u],u;for (i in ip[u])printf ", (%s) %s",ip[u][i],i;print""}}' logfile | sort -k2
awk: /Invalid user/{user[$8]++;ip[$8][$10]++} END{for (u in user){printf "%s %s",user[u],u;for (i in ip[u])printf ", (%s) %s",ip[u][i],i;print""}}
awk: ^ syntax error
awk: /Invalid user/{user[$8]++;ip[$8][$10]++} END{for (u in user){printf "%s %s",user[u],u;for (i in ip[u])printf ", (%s) %s",ip[u][i],i;print""}}
awk: ^ syntax error
awk: /Invalid user/{user[$8]++;ip[$8][$10]++} END{for (u in user){printf "%s %s",user[u],u;for (i in ip[u])printf ", (%s) %s",ip[u][i],i;print""}}
awk: ^ syntax error
$ awk '/Invalid user/{user[$8]++;ip[$8][$10]++} END{for (u in user){printf "%s %s",user[u],u;for (i in ip[u])printf ", (%s) %s",ip[u][i],i;print""}}' logfile
2 vnc, (1) 50.63.172.108, (1) 200.242.94.133
1 ftpuser, (1) 200.242.94.133
3 test, (1) 50.63.172.108, (2) 200.242.94.133
如果要按用户字母顺序排序:
$ awk '/Invalid user/{user[$8]++;ip[$8][$10]++} END{for (u in user){printf "%s %s",user[u],u;for (i in ip[u])printf ", (%s) %s",ip[u][i],i;print""}}' logfile | sort -k2
1 ftpuser, (1) 200.242.94.133
3 test, (1) 50.63.172.108, (2) 200.242.94.133
2 vnc, (1) 50.63.172.108, (1) 200.242.94.133
以上适用于GNU awk
。 我尚未使用BSD进行测试。
/Invalid user/{user[$8]++;ip[$8][$10]++}
对于logfile
具有无效用户的任何行,这将计算用户名(字段8)和ip地址(字段10)。
END{for (u in user){printf "%s %s",user[u],u;for (i in ip[u])printf ", (%s) %s",ip[u][i],i;print""}}
当我们完成读取logfile
,这将循环遍历我们所见过的每个用户,并打印我们所见到的该用户的次数,其后的用户名,每个IP地址的计数,该IP的计数,然后是该IP。
John1024的答案是一个非常简洁且快速的解决方案,它是一种选择,如果:
PROCINFO["sorted_in"]
来控制枚举顺序 )。 这里是一个行人解决方案,但是:
它基于OP命令的稍微简化的版本。
awk '/Invalid user/ { print $8 ", " $10 }' logfile | sort -t":" -k2,2 | uniq -c |
awk '
# Helper output function for printing an output line.
function printLine(c, n, l) {
sub(/,$/, "", n); print c, n l
}
# End of previous block found (new username)?
prevName != $2 {
# Print summary line for previous block.
if (NR>1) printLine(count, prevName, ipList)
# Start new block.
prevName=$2; count=0; ipList=""
}
# Build block summary values.
{
count+=$1
ipList=ipList ", (" $1 ") " $3
}
# Print summary line for last block.
END {
printLine(count, prevName, ipList)
}
'
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