R：在地图上用颜色强度绘制点

Question

我在R中有一个包含数千个地理定位观测数据的数据集，我必须在地图上绘制它们。 我设法使用此代码绘制单点：

originale<-read.table("file.txt", header=TRUE,sep=";")
require(ggplot2)
require(ggmap)
map <- get_map(location = c(lon=13.781693, lat=45.623124), zoom = 14, maptype = "terrain",source = "google")
p <- ggmap(map)
p_punti <- p + geom_point(data=originale, aes(x=lon, y=lat),size=5)
plot(p_punti)

现在我想根据位于该点的观察次数使用一组5-6种颜色绘制它们。 就像我在CartoDB上创建的那样： http ：//i.stack.imgur.com/Be1DL.png

用CartoDB绘制的地图确实太近似了：我需要为每种颜色设置自己的范围。

Answer 1

我找到了一个工作解决方案，用于计算新数据帧中每个观测值的重复，然后使用geom_point结合scale_colour_discrete和break来绘制地图。

谢谢乔什和艾斯塔的建议！

这是代码：

require(plyr)
df <-read.table("input.txt", header=TRUE,sep=";")

##selection
original <- df[(df$Year==2013),] #

##count recurrence 
conteggi2 <- ddply(original, .(original$lon, original$lat), nrow)
names(conteggi2) <- c("lon", "lat", "Freq")

##sort
conteggi2 <- conteggi2[with(conteggi2, order(Freq)), ]

##Classification
verdi <- conteggi2$Freq <= 5
conteggi2$classe[verdi] <- "1-5"
gialli <- conteggi2$Freq > 5 & conteggi2$Freq <= 20
conteggi2$classe[gialli] <- "6-20"
rossi <- conteggi2$Freq > 20 & conteggi2$Freq <= 50
conteggi2$classe[rossi] <- "21-50"
neri <- conteggi2$Freq > 50 & conteggi2$Freq <= 500
conteggi2$classe[neri] <- "51-500"

##plot map
require(ggplot2)
require(ggmap)
library(reshape2)
Trieste <- qmap(location = c(lon=13.781693, lat=45.623124), zoom = 13,
               legend = "topleft", color="bw")#maptype = "terrain",
Trieste1 <- Trieste +
        geom_point(aes(x = lon, y = lat, colour = classe, 
                       title='Year 2013'),
                        data = conteggi2) +
        guides(size=FALSE) + #remove useless label
        scale_colour_discrete(name="Legend Title",
                              breaks=c("1-5","6-20","21-50", "51-500"))
plot(Trieste1)