[英]UIBarButtonItem not clickable in UIToolBar
我有一个UIPickerView
,我加入了UIToolBar
2个UIBarButtonItems
它。
var toolBar = UIToolbar()
toolBar.frame.origin.y = -40
toolBar.barStyle = UIBarStyle.Default
toolBar.translucent = true
toolBar.tintColor = UIColor(red: 76/255, green: 217/255, blue: 100/255, alpha: 1)
toolBar.sizeToFit()
var doneButton = UIBarButtonItem(title: "Done", style: UIBarButtonItemStyle.Bordered, target: self, action: "donePicker")
var spaceButton = UIBarButtonItem(barButtonSystemItem: UIBarButtonSystemItem.FlexibleSpace, target: nil, action: nil)
var cancelButton = UIBarButtonItem(title: "Cancel", style: UIBarButtonItemStyle.Bordered, target: self, action: "canclePicker")
toolBar.setItems([cancelButton, spaceButton, doneButton], animated: false)
toolBar.userInteractionEnabled = true
pickerView.addSubview(toolBar)
pickerView.bringSubviewToFront(toolBar)
view.bringSubviewToFront(toolBar)
问题是,当我尝试单击UIBarButtonItem时,它不会触发,甚至无法识别它,它只是单击了它下面的单元格。
你可以试试这个代码。
var textField = UITextField(frame: CGRectMake(20, 50, view.width - 40, 30))
textField.backgroundColor = UIColor.redColor()
view.addSubview(textField)
var pickerView = UIPickerView(frame: CGRectMake(0, 200, view.width, 300))
pickerView.backgroundColor = UIColor.whiteColor()
pickerView.showsSelectionIndicator = true
var toolBar = UIToolbar()
toolBar.barStyle = UIBarStyle.Default
toolBar.translucent = true
toolBar.tintColor = UIColor(red: 76/255, green: 217/255, blue: 100/255, alpha: 1)
toolBar.sizeToFit()
var doneButton = UIBarButtonItem(title: "Done", style: UIBarButtonItemStyle.Bordered, target: self, action: "donePicker")
var spaceButton = UIBarButtonItem(barButtonSystemItem: UIBarButtonSystemItem.FlexibleSpace, target: nil, action: nil)
var cancelButton = UIBarButtonItem(title: "Cancel", style: UIBarButtonItemStyle.Bordered, target: self, action: "canclePicker")
toolBar.setItems([cancelButton, spaceButton, doneButton], animated: false)
toolBar.userInteractionEnabled = true
textField.inputView = pickerView
textField.inputAccessoryView = toolBar
我相信您需要使用标准的UIResponder机制提高选择器和工具栏,或者通过使用隐藏的UITextField作弊以获取相同的结果。
查看我对原始问题的更新答案:
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