[英]How get an array from a MySQL column with mysqli_fetch_array
我正在尝试撰写IP禁令。 用户IP存储在数据库中。 我可以将该用户IP手动添加到黑名单中。 不幸的是,以下代码不起作用。 我认为问题在于将阵列移出数据库。
$ip = $_SERVER['REMOTE_ADDR'];
$bannedips = array();
$notBanned = true; //later used to check, if ip is banned
$sql = "SELECT ip FROM ipban";
$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$bannedips[] = $row;
}
if (in_array($ip, $bannedips)) {
$notBanned = false;
}
而不是查询所有条目,您应该只搜索ip以获得性能原因
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned
$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = mysqli_prepare($conn, $sql)) {
/* bind parameters for markers */
mysqli_stmt_bind_param($stmt, "s", $ip);
if($result = mysqli_query($conn, $sql)){
$notBanned = false;
mysqli_free_result($result);
}
}
面向对象的样式应为:
$mysqli = new mysqli(/* Whatever needed to establish connection */);
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned
$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = $mysqli->prepare($sql)){
$stmt->bind_param("s", $ip);
$stmt->execute();
if($stmt && $stmt->num_rows > 0){
$notBanned = false;
}
}
只是改变:
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$bannedips[] = $row;
而且您无法将mysqli函数与mysql合并
$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){
最后(编辑):
$host = "example";
$username = "example";
$password = "example";
$database = "example";
$ip = $_SERVER['REMOTE_ADDR'];
$bannedips = array();
$notBanned = true; //later used to check, if ip is banned
$connection = new mysqli($host, $username, $password, $database);
$query = $connection->query("SELECT ip FROM ipban");
while ($row = $query->fetch_array()) {
$bannedips[] = $row['ip'];
}
if (in_array($ip, $bannedips)) {
$notBanned = false;
}
您可以在以下位置阅读更多信息:
该问题保存在您的while循环内。 在将数据追加到$ bannedips数组的同时,您忘记了从$ row数组中选择第零个(ip列)键。
将$ row更改为row [0],如下所示:
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$bannedips[] = $row[0];
}
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