[英]How get an array from a MySQL column with mysqli_fetch_array
我正在嘗試撰寫IP禁令。 用戶IP存儲在數據庫中。 我可以將該用戶IP手動添加到黑名單中。 不幸的是,以下代碼不起作用。 我認為問題在於將陣列移出數據庫。
$ip = $_SERVER['REMOTE_ADDR'];
$bannedips = array();
$notBanned = true; //later used to check, if ip is banned
$sql = "SELECT ip FROM ipban";
$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$bannedips[] = $row;
}
if (in_array($ip, $bannedips)) {
$notBanned = false;
}
而不是查詢所有條目,您應該只搜索ip以獲得性能原因
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned
$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = mysqli_prepare($conn, $sql)) {
/* bind parameters for markers */
mysqli_stmt_bind_param($stmt, "s", $ip);
if($result = mysqli_query($conn, $sql)){
$notBanned = false;
mysqli_free_result($result);
}
}
面向對象的樣式應為:
$mysqli = new mysqli(/* Whatever needed to establish connection */);
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned
$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = $mysqli->prepare($sql)){
$stmt->bind_param("s", $ip);
$stmt->execute();
if($stmt && $stmt->num_rows > 0){
$notBanned = false;
}
}
只是改變:
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$bannedips[] = $row;
而且您無法將mysqli函數與mysql合並
$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){
最后(編輯):
$host = "example";
$username = "example";
$password = "example";
$database = "example";
$ip = $_SERVER['REMOTE_ADDR'];
$bannedips = array();
$notBanned = true; //later used to check, if ip is banned
$connection = new mysqli($host, $username, $password, $database);
$query = $connection->query("SELECT ip FROM ipban");
while ($row = $query->fetch_array()) {
$bannedips[] = $row['ip'];
}
if (in_array($ip, $bannedips)) {
$notBanned = false;
}
您可以在以下位置閱讀更多信息:
該問題保存在您的while循環內。 在將數據追加到$ bannedips數組的同時,您忘記了從$ row數組中選擇第零個(ip列)鍵。
將$ row更改為row [0],如下所示:
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$bannedips[] = $row[0];
}
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