在 Python 请求中使用 POST 表单数据上传图像

Question

我正在使用微信 API ...在这里我必须使用此 API http://admin.wechat.com/wiki/index.php?title=Transferring_Multimedia_Files将图像上传到微信服务器

url = 'http://file.api.wechat.com/cgi-bin/media/upload?access_token=%s&type=image'%access_token
files = {
    'file': (filename, open(filepath, 'rb')),
    'Content-Type': 'image/jpeg',
    'Content-Length': l
}
r = requests.post(url, files=files)

我无法发布数据

Answer 1

来自微信api文档：

curl -F media=@test.jpg "http://file.api.wechat.com/cgi-bin/media/upload?access_token=ACCESS_TOKEN&type=TYPE"

将上面的命令翻译成python：

import requests
url = 'http://file.api.wechat.com/cgi-bin/media/upload?access_token=ACCESS_TOKEN&type=TYPE'
files = {'media': open('test.jpg', 'rb')}
requests.post(url, files=files)

文档： https ://docs.python-requests.org/en/master/user/quickstart/#post-a-multipart-encoded-file

Answer 2

如果您要将图像作为 JSON 的一部分与其他属性一起传递，则可以使用以下代码段。
客户端.py

import base64
import json                    

import requests

api = 'http://localhost:8080/test'
image_file = 'sample_image.png'

with open(image_file, "rb") as f:
    im_bytes = f.read()        
im_b64 = base64.b64encode(im_bytes).decode("utf8")

headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
  
payload = json.dumps({"image": im_b64, "other_key": "value"})
response = requests.post(api, data=payload, headers=headers)
try:
    data = response.json()     
    print(data)                
except requests.exceptions.RequestException:
    print(response.text)

服务器.py

import io
import json                    
import base64                  
import logging             
import numpy as np
from PIL import Image

from flask import Flask, request, jsonify, abort

app = Flask(__name__)          
app.logger.setLevel(logging.DEBUG)
  
  
@app.route("/test", methods=['POST'])
def test_method():         
    # print(request.json)      
    if not request.json or 'image' not in request.json: 
        abort(400)
             
    # get the base64 encoded string
    im_b64 = request.json['image']

    # convert it into bytes  
    img_bytes = base64.b64decode(im_b64.encode('utf-8'))

    # convert bytes data to PIL Image object
    img = Image.open(io.BytesIO(img_bytes))

    # PIL image object to numpy array
    img_arr = np.asarray(img)      
    print('img shape', img_arr.shape)

    # process your img_arr here    
    
    # access other keys of json
    # print(request.json['other_key'])

    result_dict = {'output': 'output_key'}
    return result_dict
  
  
def run_server_api():
    app.run(host='0.0.0.0', port=8080)
  
  
if __name__ == "__main__":     
    run_server_api()

Answer 3

当我想从 Python 将图像文件发布到休息 API（虽然不是微信 API）时，我遇到了类似的问题。 我的解决方案是使用“数据”参数以二进制数据而不是“文件”形式发布文件。 请求 API 参考

data = open('your_image.png','rb').read()
r = requests.post(your_url,data=data)

希望这适用于您的情况。

Answer 4

使用这个片段

import os
import requests
url = 'http://host:port/endpoint'
with open(path_img, 'rb') as img:
  name_img= os.path.basename(path_img)
  files= {'image': (name_img,img,'multipart/form-data',{'Expires': '0'}) }
  with requests.Session() as s:
    r = s.post(url,files=files)
    print(r.status_code)

Answer 5

import requests

image_file_descriptor = open('test.jpg', 'rb')
# Requests makes it simple to upload Multipart-encoded files 
files = {'media': image_file_descriptor}
url = '...'
requests.post(url, files=files)
image_file_descriptor.close()

不要忘记关闭描述符，它可以防止错误： 显式关闭文件重要吗？

Answer 6

让 Rest API 将图像从主机上传到主机：

import urllib2
import requests

api_host = 'https://host.url.com/upload/'
headers = {'Content-Type' : 'image/jpeg'}
image_url = 'http://image.url.com/sample.jpeg'

img_file = urllib2.urlopen(image_url)

response = requests.post(api_host, data=img_file.read(), headers=headers, verify=False)

您可以使用设置为 False 的选项验证来省略 HTTPS 请求的 SSL 验证。

Answer 7

如果您有CURL ，那么您可以直接从 Postman 获取请求。

import requests

url = "your URL"

payload={}
files=[
  ('upload_file',('20220212235319_1509.jpg',open('/20220212235319_1509.jpg','rb'),'image/jpeg'))
]
headers = {
  'Accept-Language': 'en-US',
  'Authorization': 'Bearer yourToken'
}

response = requests.request("POST", url, headers=headers, data=payload, files=files)

print(response.text)

Answer 8

这对我有用。

import requests

url = "https://example.com"
payload={}
files=[
  ('file',('myfile.jpg',open('/path/to/myfile.jpg','rb'),'image/jpeg'))
]

response = requests.request("POST", url, auth=("my_username","my_password"), data=payload, files=files)
print(response.text)