[英]Combine two SQL Queries efficiently
我有两个查询:
1)
SELECT COUNT(*) AS total, COUNT(supporter) AS done FROM Supports;
2)
SELECT supporter, COUNT(supporter) AS amount FROM Supports
GROUP BY supporter ORDER BY amount DESC LIMIT 1;
如何有效地结合它们?
这是表格的样子:
+-----------------------------+
| id | name | supporter |
+-----------------------------+
| 1 | user1 | sup1 |
| 2 | user1 | sup2 |
| 3 | user1 | NULL |
| 4 | user2 | sup1 |
| 5 | user2 | sup3 |
+-----------------------------+
由于需要总数,因此必须使用子查询来合并为一个查询。 将其包括在FROM子句中。
SELECT supporter, COUNT(supporter) AS amount, total, done
FROM Supports,
(SELECT COUNT(*) AS total, COUNT(supporter) AS done FROM Supports) totals
GROUP BY supporter
ORDER BY amount DESC
LIMIT 1;
我相信这是您要寻找的:
SELECT
(SELECT COUNT(*) FROM Supports) as total,
(SELECT COUNT(supporter) FROM Supports) as done,
supporter,
COUNT(*) AS amount
FROM Supports
GROUP BY supporter
ORDER BY amount;
结果看起来像这样: http : //sqlfiddle.com/#!9/9e4ee/9
total done supporter amount
5 4 sup3 1
5 4 sup2 1
5 4 NULL 1
5 4 sup1 2
SELECT a.total, a.done, b.supporter, b.amount
( SELECT COUNT(*) AS total,
COUNT(supporter) AS done
FROM Supports
) AS a
JOIN
( SELECT supporter,
COUNT(supporter) AS amount
FROM Supports
GROUP BY supporter
ORDER BY amount DESC
LIMIT 1
) AS b;
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