I have two Queries:
1)
SELECT COUNT(*) AS total, COUNT(supporter) AS done FROM Supports;
2)
SELECT supporter, COUNT(supporter) AS amount FROM Supports
GROUP BY supporter ORDER BY amount DESC LIMIT 1;
How can I efficiently combine them?
This is how the Table looks like:
+-----------------------------+
| id | name | supporter |
+-----------------------------+
| 1 | user1 | sup1 |
| 2 | user1 | sup2 |
| 3 | user1 | NULL |
| 4 | user2 | sup1 |
| 5 | user2 | sup3 |
+-----------------------------+
Since you want the total, you'll have to use a subquery to combine into one query. Include it in the FROM clause.
SELECT supporter, COUNT(supporter) AS amount, total, done
FROM Supports,
(SELECT COUNT(*) AS total, COUNT(supporter) AS done FROM Supports) totals
GROUP BY supporter
ORDER BY amount DESC
LIMIT 1;
I believe this is what you are looking for:
SELECT
(SELECT COUNT(*) FROM Supports) as total,
(SELECT COUNT(supporter) FROM Supports) as done,
supporter,
COUNT(*) AS amount
FROM Supports
GROUP BY supporter
ORDER BY amount;
Results looks like this: http://sqlfiddle.com/#!9/9e4ee/9
total done supporter amount
5 4 sup3 1
5 4 sup2 1
5 4 NULL 1
5 4 sup1 2
SELECT a.total, a.done, b.supporter, b.amount
( SELECT COUNT(*) AS total,
COUNT(supporter) AS done
FROM Supports
) AS a
JOIN
( SELECT supporter,
COUNT(supporter) AS amount
FROM Supports
GROUP BY supporter
ORDER BY amount DESC
LIMIT 1
) AS b;
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