[英]QThread: Destroyed while thread is still running and QMutex destroyed
我正在尝试将多个线程添加到我的Qt应用程序中,但是恰好在执行此线程时,程序崩溃了,并且出现错误
QThread:在线程仍在运行时被销毁
QMutex:销毁锁定的互斥锁
我了解错误消息,但我不知道该如何解决。 我的代码如下。
头
class Worker : public QObject
{
Q_OBJECT
private slots:
void onTimeout()
{
qDebug()<<"Worker::onTimeout get called from?: "<<QThread::currentThreadId();
}
};
class Thread : public QThread
{
Q_OBJECT
private:
void run()
{
qDebug()<<"From work thread: "<<currentThreadId();
QTimer timer;
Worker worker;
connect(&timer, SIGNAL(timeout()), &worker, SLOT(onTimeout()));
timer.start(1000);
exec();
}
};
login.cpp
void Login::on_pushButton_clicked()
{
QSqlQuery query;
QString Username = ui->Username_lineEdit->text();
QString Password = ui->Password_lineEdit->text();
query.prepare("SELECT * FROM Program_account WHERE Login = '"+ Username +"' AND Password = '"+ Password +"'");
if(!query.exec())
{
qDebug() << "SQL QUERY Login:" << query.executedQuery();
qDebug() << "SQL ERROR Login:" << query.lastError();
}
else if(!query.first())
{
tries++;
int x = 10 - tries;
ui->label->setText("Incorrect Username or Password " + QString::number(x) + " tries until timeout");
}
else
{
QSqlQuery Account_Type_Query("SELECT Account_Type FROM Program_account WHERE Login = '"+ Username +"' AND Password = '"+ Password +"'");
while(Account_Type_Query.next())
{
Account_Type = Account_Type_Query.value(0).toInt();
}
tries = 0;
static Home *home = new Home;
home->show();
close();
}
if(tries == 10)
{
Thread t;
t.start();
ui->label->setText("Password entered wrong too many times, entered 10 minute cooldown period");
ui->pushButton->hide();
QTimer::singleShot(600000, ui->pushButton, SLOT(show()));
tries = 0;
ui->label->setText("");
}
我可以解决此问题的正确方法是什么。 非常感谢所有帮助。
谢谢
更新:尝试过的类线程:公共QThread {Q_OBJECT
private:
void run()
{
while(QThread::wait())
{
qDebug()<<"From work thread: "<<currentThreadId();
QTimer timer;
Worker worker;
connect(&timer, SIGNAL(timeout()), &worker, SLOT(onTimeout()));
timer.start(1000);
exec();
}
QThread::quit();
}
};
但仍然收到相同的错误
从QThread继承是这里的一个问题,我怀疑Worker对象没有您认为具有的线程亲和力并且正在主线程上运行。
崩溃的原因是您在堆栈上创建了Thread实例,
if(tries == 10)
{
Thread t; // NOTE THIS IS ON THE STACK
t.start();
ui->label->setText("Password entered wrong too many times, entered 10 minute cooldown period");
ui->pushButton->hide();
QTimer::singleShot(600000, ui->pushButton, SLOT(show()));
tries = 0;
ui->label->setText("");
}
线程实例超出范围时将被销毁。
无论如何,我强烈建议遵循@Thomas的建议,并坚持Maya使用线程的方式,而无需继承QThread。
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