使用内部用户输入作为函数Python中的输入

Question

我目前在Python 3中遇到一些麻烦。我试图弄清楚如何使用存储在pension_contribution pension()中income和pension_contribution中的用户输入，但是什么也没有发生。 这些用户输入应该放在哪里才能被认为是输入，以便功能可以工作？

income = input(int("What is your annual income?"))
pension_contribution = input(int("What is your monthly pension contribution?"))

def pension(pension_contribution, income):
    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")
    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

Answer 1

1）您的缩进似乎不对
2）您需要调用该函数

income = input(int("What is your annual income?"))
pension_contribution = input(int("What is your monthly pension contribution?"))

def pension (pension_contribution, income):

    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

pension(pension_contribution, income)

Answer 2

您可以通过3种不同的方式执行此操作：

1.只需调用该函数

def pension (pension_contribution, income):

    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

income = int(input("What is your annual income?"))
pension_contribution = int(input("What is your monthly pension contribution?")) 

pension(pension_contribution, income) #call function

2.将变量放入函数中

def pension ():
    income = int(input("What is your annual income?"))
    pension_contribution = int(input("What is your monthly pension contribution?"))
    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)


pension() #still have to call function

2.全局变量 （不推荐）

income = int(input("What is your annual income?"))
pension_contribution = int(input("What is your monthly pension contribution?"))

def pension ():
    global income, pension_contribution
    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

pension() #still have to call function

请注意，每次必须如何“调用”该函数。 否则，程序将成功运行，但永远不会打扰进入该功能。