[英]Display all rows with the same id
这是我的桌子:
Place_Id | Value_Name| Value
-------------------------------
001 | Name1 | Value1
-------------------------------
001 | Name2 | Value2
-------------------------------
001 | Name3 | Value3
-------------------------------
002 | Name1 | Value4
-------------------------------
002 | Name2 | Value5
如何回Value_Name
Place_Id
001的所有Value_Name
列表?
我尝试了这个:
<?php
$query2 = ("SELECT * FROM table WHERE Place_Id = 001");
if ($statement2 = $db_conn_pdo->prepare($query2))
{
$statement2->execute();
while ($row2 = $statement2->fetch(PDO::FETCH_ASSOC))
{
$output2 = $row2['Value_Name'];
}
}
echo $output2;
?>
并且它仅返回最后一个“ Value_Name”。
这样的事情应该工作
$query = $con ->query
("
SELECT Value_Name FROM [table] WHERE Place_Id = '001'
");
$valueName = array();
while($row = $query->fetch_object())
{
$valueName[] = $row;
}
foreach($valueName as $Value)
{
echo $Value->Value_Name;
}
因此,这里是最终版本,感谢@Alexander Ravikovich和@McNoodles:
$query = $con ->query
("
SELECT Value_Name FROM [table] WHERE Place_Id = '001'
");
while($row = $query->fetch_object())
{
echo $row['Value_Name'];
}
// the second loop is not needed as @Alexander Ravikovich suggested
假设表名是微妙的(因为您没有提到它)
SQL查询: SELECT Value_Name FROM jiggles WHERE jiggles.place_id = [the id you want to know]
执行低谷的PHP并在某处回显结果
(只要您仅回显value_name属性,“ Select”中的*也会起作用)
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