Here is my table:
Place_Id | Value_Name| Value
-------------------------------
001 | Name1 | Value1
-------------------------------
001 | Name2 | Value2
-------------------------------
001 | Name3 | Value3
-------------------------------
002 | Name1 | Value4
-------------------------------
002 | Name2 | Value5
How can I echo out list of all Value_Name
for Place_Id
001 ?
I tried this:
<?php
$query2 = ("SELECT * FROM table WHERE Place_Id = 001");
if ($statement2 = $db_conn_pdo->prepare($query2))
{
$statement2->execute();
while ($row2 = $statement2->fetch(PDO::FETCH_ASSOC))
{
$output2 = $row2['Value_Name'];
}
}
echo $output2;
?>
and it returned only the last "Value_Name".
Something like this should work
$query = $con ->query
("
SELECT Value_Name FROM [table] WHERE Place_Id = '001'
");
$valueName = array();
while($row = $query->fetch_object())
{
$valueName[] = $row;
}
foreach($valueName as $Value)
{
echo $Value->Value_Name;
}
So here is the final version thanks to @Alexander Ravikovich and @McNoodles:
$query = $con ->query
("
SELECT Value_Name FROM [table] WHERE Place_Id = '001'
");
while($row = $query->fetch_object())
{
echo $row['Value_Name'];
}
// the second loop is not needed as @Alexander Ravikovich suggested
Assuming table name is jiggles (since you didn't mention it)
SQL Query : SELECT Value_Name FROM jiggles WHERE jiggles.place_id = [the id you want to know]
Execute this trough PHP and echo the results somewhere
(* in the Select works too, as long as you just only echo the value_name property)
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