[英]Type 'X' does not conform to protocol 'ResponseObjectSerializable'
我尝试使用Alamofire进行自定义响应序列化
我遵循README中的内容并创建协议和扩展
@objc public protocol ResponseObjectSerializable {
init?(response: NSHTTPURLResponse, representation: AnyObject)
}
extension Alamofire.Request {
public func responseObject<T: ResponseObjectSerializable>(completionHandler: (NSURLRequest, NSHTTPURLResponse?, T?, NSError?) -> Void) -> Self {
let serializer: Serializer = { (request, response, data) in
let JSONSerializer = Request.JSONResponseSerializer(options: .AllowFragments)
let (JSON: AnyObject?, serializationError) = JSONSerializer(request, response, data)
if response != nil && JSON != nil {
return (T(response: response!, representation: JSON!), nil)
} else {
return (nil, serializationError)
}
}
return response(serializer: serializer, completionHandler: { (request, response, object, error) in
completionHandler(request, response, object as? T, error)
})
}
}
但是当我尝试遵守它时我得到了这个错误类型'my_model_class'不符合协议'ResponseObjectSerializable'
我的模型只是一个裸骨类
final class Shot: ResponseObjectSerializable {
required init?(response: NSHTTPURLResponse, representation: AnyObject) {
}
}
与Xcode 6.3一起使用,有谁经历过这个? 并知道如何使这项工作?
对@airspeed的回应错误消失了,但令我困惑的是Apple Swift文档中有一个关于@objc
协议的例子和符合它的swift类不需要@objc
@objc protocol CounterDataSource {
optional func incrementForCount(count: Int) -> Int
optional var fixedIncrement: Int { get }
}
class TowardsZeroSource: CounterDataSource {
func incrementForCount(count: Int) -> Int {
if count == 0 {
return 0
} else if count < 0 {
return 1
} else {
return -1
}
}
}
与协议不同, Shot
未标记为@objc
,因此您的init
与要求不匹配:
@objc public protocol ResponseObjectSerializable {
init?(response: NSHTTPURLResponse, representation: AnyObject)
}
final class Shot: ResponseObjectSerializable {
@objc required init?(response: NSHTTPURLResponse, representation: AnyObject) {
}
}
导致错误:
注意:协议需要初始化程序
init(response:representation:)
与类型(response: NSHTTPURLResponse, representation: AnyObject)
init?(response: NSHTTPURLResponse, representation: AnyObject)` ^
注意:候选人不是
@objc
,但协议需要它
将@objc
在Shot
的定义之前,它应该编译。
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