[英]Wait for function to end in Swift
我有一个函数用json获取数据,我将所有数据附加到数组。 我尝试创建信号量并等到发送信号到信号量继续但它不起作用(我不确定我是否正确),然后我在Stackoverflow中看到一个问题,答案是创建一个完成处理程序像那样
func application(application: UIApplication!, performFetchWithCompletionHandler completionHandler: ((UIBackgroundFetchResult) -> Void)!) {
getUrunGrup(completionHandler)
}
所以我改变了我的功能
func getUrunGrup(completionHandler: ((UIBackgroundFetchResult) -> Void)!){
Alamofire.request(.GET, "http://213.136.86.160:27701/Thunder/DataService/GetUrunGrup")
.responseJSON {(request, response, jsonObj, error) in
if let jsonresult:NSDictionary = jsonObj as? NSDictionary{
if let result: AnyObject = jsonresult["Result"] {
let elementCount = result.count
for (var i = 0; i<elementCount; ++i){
if let name: AnyObject = result[i]["Adi"]!{
if let kod:AnyObject = result[i]["Kod"]!{
urunUstGrup.append(["Adi": "\(name)", "Kod": "\(kod)"])
println("getUrunGrup \(i)")
}
}
}
}
}
}
completionHandler(UIBackgroundFetchResult.NewData)
println("Background Fetch Complete")
}
但我怎么称呼这个功能没有答案?
您必须将您的异步函数传递给稍后调用的处理程序,如下所示:
func application(application: UIApplication!, performFetchWithCompletionHandler completionHandler: ((UIBackgroundFetchResult) -> Void)!) {
loadShows(completionHandler)
}
func loadShows(completionHandler: ((UIBackgroundFetchResult) -> Void)!) {
//....
//DO IT
//....
completionHandler(UIBackgroundFetchResult.NewData)
println("Background Fetch Complete")
}
添加一个中间completionHandler
func application(application: UIApplication!, performFetchWithCompletionHandler completionHandler: ((UIBackgroundFetchResult) -> Void)!) {
loadShows() {
completionHandler(UIBackgroundFetchResult.NewData)
println("Background Fetch Complete")
}
}
func loadShows(completionHandler: (() -> Void)!) {
//....
//DO IT
//....
completionHandler()
}
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