Oracle SQL查询表并根据结果从另一个表中删除

Question

所以我有下表

   CREATE TABLE Accounts (
        Acc_ID INTEGER PRIMARY KEY,
        Acc_Name VARCHAR(50) NOT NULL
    );

    CREATE TABLE City (
        Zip VARCHAR(20) PRIMARY KEY,
        CityName VARCHAR(30) NOT NULL
    );

    CREATE  TABLE Address (
        Addr_ID INTEGER PRIMARY KEY,
        Street VARCHAR(50) NOT NULL,
        HouseNo VARCHAR(10) NOT NULL,
        Zip VARCHAR(20) NOT NULL REFERENCES City ON DELETE CASCADE
    );


    CREATE TABLE Located (    
        Acc_ID INTEGER NOT NULL REFERENCES Accounts ON DELETE CASCADE,
        Addr_ID INTEGER NOT NULL REFERENCES Address ON DELETE CASCADE,
        PRIMARY KEY(Acc_ID, Addr_ID)

我想在下面使用类似的查询，以便能够根据选择查询的结果删除行。

delete from Address where add_id=(select addr_id from Located where ACC_ID=1);

那可能吗 ？ 如果是的话如何？

Answer 1

您几乎了解了它，甚至在某些情况下（当子查询找到一行时）您的建议也可以使用。 这是更一般的情况，您只需要IN而不是= ：

delete from Address 
  where add_id IN (select addr_id from Located where ACC_ID=1);