Oracle SQL查詢表並根據結果從另一個表中刪除

Question

所以我有下表

   CREATE TABLE Accounts (
        Acc_ID INTEGER PRIMARY KEY,
        Acc_Name VARCHAR(50) NOT NULL
    );

    CREATE TABLE City (
        Zip VARCHAR(20) PRIMARY KEY,
        CityName VARCHAR(30) NOT NULL
    );

    CREATE  TABLE Address (
        Addr_ID INTEGER PRIMARY KEY,
        Street VARCHAR(50) NOT NULL,
        HouseNo VARCHAR(10) NOT NULL,
        Zip VARCHAR(20) NOT NULL REFERENCES City ON DELETE CASCADE
    );


    CREATE TABLE Located (    
        Acc_ID INTEGER NOT NULL REFERENCES Accounts ON DELETE CASCADE,
        Addr_ID INTEGER NOT NULL REFERENCES Address ON DELETE CASCADE,
        PRIMARY KEY(Acc_ID, Addr_ID)

我想在下面使用類似的查詢，以便能夠根據選擇查詢的結果刪除行。

delete from Address where add_id=(select addr_id from Located where ACC_ID=1);

那可能嗎 ？ 如果是的話如何？

Answer 1

您幾乎了解了它，甚至在某些情況下（當子查詢找到一行時）您的建議也可以使用。 這是更一般的情況，您只需要IN而不是= ：

delete from Address 
  where add_id IN (select addr_id from Located where ACC_ID=1);