将秒转换为年时分秒

Question

我是一个新的，标准的开始，所以我将其余的排除在外。 我必须将每个int转换为秒，还是对吗？ 因为当我手动进行反向计算并计算最终语句的秒数时，我得到了小时数差异。

Thx Casu

    Scanner input = new Scanner(System.in);
    final int secmin = 60;
    final int day = 24;
    final int year = 365;
    int seconds = input.nextInt();
    int minutes = seconds / secmin;
    int remainSec = seconds % secmin ;

    int hours = minutes / secmin;
    int remainMin = hours % secmin;
    int days = hours / day;
    int remainHours = hours % day;
    int years = days / year;
    int remainDays = days % year;

    if (minutes <= 59)
    {
        System.out.println(seconds + " seconds is " + minutes +" minutes and " + remainSec + " seconds");
    }
    else if (hours <= 23) 
    {   

        System.out.println(seconds + " seconds is " + hours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }
    else if (days <= 364)
    {   

        System.out.println(seconds + " seconds is " + days + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }

    else
    {
        System.out.println(seconds + " seconds is " + years + " years " + remainDays + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }

Answer 1

我认为该语句需要更改：从“ int keepMin =小时％秒min;”开始

为“ int keepMin =分钟％秒/分钟；”。

休息都很好。

Answer 2

代码看起来不错。 但是，我将从if语句中删除“魔术数字”：

Scanner input = new Scanner(System.in);
final int secmin = 60;
final int day = 24;
final int year = 365;
int seconds = input.nextInt();
int minutes = seconds / secmin;
int remainSec = seconds % secmin ;

int hours = minutes / secmin;
int remainMin = hours % secmin;
int days = hours / day;
int remainHours = hours % day;
int years = days / year;
int remainDays = days % year;

if (minutes < secMin)
{
    System.out.println(seconds + " seconds is " + minutes +" minutes and " + remainSec + " seconds");
}
else if (hours < day) 
{   

    System.out.println(seconds + " seconds is " + hours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}
else if (days < year)
{   

    System.out.println(seconds + " seconds is " + days + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}

else
{
    System.out.println(seconds + " seconds is " + years + " years " + remainDays + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}

我知道年/天/小时/分钟/秒的比率都是非常静态的，但是如果有人想在10秒到分钟和10分钟到小时之间查看您的代码怎么办？ 然后，您只需要更改一个地方而不是两个地方即可。

在生产应用程序中，这可能会扩展到代码中的数百个位置，并且很难逐一追踪每个位置。

Answer 3

我确实输入=

1234234234秒

输出=

1234234234秒是39年50天2小时2分34秒

总和=

1229904000 s + 4320000 s + 7200 s + 120 s + 34 s = 1234231354 s

差异=

2880 s

当我改变时：

int keepMin =小时％秒最小值； “ to” int keepMin =分钟％秒最小；

然后：

1234234234秒是39年50天2小时50分钟34秒

结果：

48分钟添加

1229904000 s + 4320000 s + 7200 s + 3000 s + 34 s = 1234234234 s

且差异为0。

感谢您对user2006544的更正和对Steve的改进。