將秒轉換為年時分秒

Question

我是一個新的，標准的開始，所以我將其余的排除在外。 我必須將每個int轉換為秒，還是對嗎？ 因為當我手動進行反向計算並計算最終語句的秒數時，我得到了小時數差異。

Thx Casu

    Scanner input = new Scanner(System.in);
    final int secmin = 60;
    final int day = 24;
    final int year = 365;
    int seconds = input.nextInt();
    int minutes = seconds / secmin;
    int remainSec = seconds % secmin ;

    int hours = minutes / secmin;
    int remainMin = hours % secmin;
    int days = hours / day;
    int remainHours = hours % day;
    int years = days / year;
    int remainDays = days % year;

    if (minutes <= 59)
    {
        System.out.println(seconds + " seconds is " + minutes +" minutes and " + remainSec + " seconds");
    }
    else if (hours <= 23) 
    {   

        System.out.println(seconds + " seconds is " + hours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }
    else if (days <= 364)
    {   

        System.out.println(seconds + " seconds is " + days + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }

    else
    {
        System.out.println(seconds + " seconds is " + years + " years " + remainDays + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }

Answer 1

我認為該語句需要更改：從“ int keepMin =小時％秒min;”開始

為“ int keepMin =分鍾％秒/分鍾；”。

休息都很好。

Answer 2

代碼看起來不錯。 但是，我將從if語句中刪除“魔術數字”：

Scanner input = new Scanner(System.in);
final int secmin = 60;
final int day = 24;
final int year = 365;
int seconds = input.nextInt();
int minutes = seconds / secmin;
int remainSec = seconds % secmin ;

int hours = minutes / secmin;
int remainMin = hours % secmin;
int days = hours / day;
int remainHours = hours % day;
int years = days / year;
int remainDays = days % year;

if (minutes < secMin)
{
    System.out.println(seconds + " seconds is " + minutes +" minutes and " + remainSec + " seconds");
}
else if (hours < day) 
{   

    System.out.println(seconds + " seconds is " + hours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}
else if (days < year)
{   

    System.out.println(seconds + " seconds is " + days + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}

else
{
    System.out.println(seconds + " seconds is " + years + " years " + remainDays + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}

我知道年/天/小時/分鍾/秒的比率都是非常靜態的，但是如果有人想在10秒到分鍾和10分鍾到小時之間查看您的代碼怎么辦？ 然后，您只需要更改一個地方而不是兩個地方即可。

在生產應用程序中，這可能會擴展到代碼中的數百個位置，並且很難逐一追蹤每個位置。

Answer 3

我確實輸入=

1234234234秒

輸出=

1234234234秒是39年50天2小時2分34秒

總和=

1229904000 s + 4320000 s + 7200 s + 120 s + 34 s = 1234231354 s

差異=

2880 s

當我改變時：

int keepMin =小時％秒最小值； “ to” int keepMin =分鍾％秒最小；

然后：

1234234234秒是39年50天2小時50分鍾34秒

結果：

48分鍾添加

1229904000 s + 4320000 s + 7200 s + 3000 s + 34 s = 1234234234 s

且差異為0。

感謝您對user2006544的更正和對Steve的改進。